Disk and Electric Field's Direction

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SUMMARY

The discussion focuses on determining the direction of the electric field generated by a uniformly charged annulus with inner radius R1 and outer radius R2. The consensus is that the electric field E, when evaluated at points above the annulus, points away from the center hole due to the positive surface charge density omega. A vector diagram is suggested for a clearer representation of this concept.

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  • Understanding of electric fields and charge distributions
  • Familiarity with vector diagrams and their applications in physics
  • Knowledge of surface charge density concepts
  • Basic principles of electrostatics
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Soaring Crane
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Homework Statement



A thin disk with a circular hole at its center, called an annulus, has inner radius R1 and outer radius R2. The disk has a uniform positive surface charge density omega on its surface.

Figure's link: http://i131.photobucket.com/albums/p289/SoaringCrane/yf_Figure_21_421.jpg

Find the direction of the electric field E. Consider points above the annulus in the figure.



Homework Equations



This part of the question is really conceptual.


The Attempt at a Solution


Since the disk's overall charge is positive, the force of a positive test charge above the annulus would be directed away from the hole. Therefore, the electric field's direction would be in the positive x-direction??

Thanks.
 
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You are correct but can you show it using a vector diagram?
 

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