Dispersion Relation of a De Broglie Wave

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SUMMARY

The discussion focuses on the dispersion relation of a De Broglie wave, specifically calculating the group velocity (v_group) and phase velocity (v_phase). The equation for omega(k) is given as ω(k) = (ħk²)/(2m). The correct expressions derived are v_group = (ħk)/m and v_phase = (h/(2mλ)). It is clarified that in a dispersive medium, the relationship fλ = v does not hold universally, leading to v_phase being equal to 1/2 v under certain conditions.

PREREQUISITES
  • Understanding of quantum mechanics concepts such as wave-particle duality.
  • Familiarity with the De Broglie wavelength and its implications.
  • Knowledge of dispersion relations in physics.
  • Proficiency in calculus, specifically differentiation and substitution techniques.
NEXT STEPS
  • Study the implications of dispersion in quantum mechanics.
  • Learn about the relationship between phase velocity and group velocity in various media.
  • Explore the derivation and applications of the De Broglie wavelength.
  • Investigate the role of the Planck constant (h) and reduced Planck constant (ħ) in wave mechanics.
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Students and professionals in physics, particularly those studying quantum mechanics, wave phenomena, and dispersion relations. This discussion is beneficial for anyone looking to deepen their understanding of wave behavior in quantum systems.

Silly Sausage
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Homework Statement



Use the dispersion relation to find the group velocity v_group and phase velocity v_phase.

Homework Equations



omega(k) = [(hbar)k^2]/2m

The Attempt at a Solution



v_group = domega(k)/dk = [hbar]k/m = h/m lambda = p/m = v

This isn't right.

v_phase = omega / k = 2pi f/(2pi/lambda) = f lamda = v

again... is this right?, doesn't look it but as far as I can see there is no mistake in the calc as I have doing it several times already, am I goign wrong in my physics?
 
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Hi there,

Your first answer is definitely right.

But then, why did you substitute omega = 2pi f and k = 2pi/lambda in the expression for the phase velocity? When I substitute the expression you were given for omega and divide it by k I get v_phase = 1/2 v.

I don't think f lambda equals v here, because if omega = (hbar*k^2)/2m I get f = h/(2m*lambda^2) and if you multiply that by lambda you'll get h/(2m*lambda) = p/2m which again gives you 1/2 v.

Relations like p = h/lambda, omega = 2pi f and k = 2pi/lambda are always true, but in a dispersive medium f lambda = v = v_group is not always true, only when omega = v * k, then v = v_group = v_phase.

Hope that helps.

Wynand.
 

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