Displacement, Average Speed, and Average Velocity

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SUMMARY

The discussion focuses on calculating displacement, average speed, and average velocity using a graph representing a turtle's journey. The turtle's total displacement is determined to be 23 meters, calculated from the difference between the final and initial positions. The average speed is calculated as 29 meters divided by 66 minutes, resulting in approximately 2.3 m/min. Average velocity, being a vector quantity, is defined as displacement divided by time, which is 23 meters over 66 minutes, yielding approximately 0.35 m/min.

PREREQUISITES
  • Understanding of basic physics concepts such as displacement and velocity.
  • Familiarity with graph interpretation, specifically distance vs. time graphs.
  • Knowledge of vector vs. scalar quantities.
  • Basic arithmetic for calculating averages and ratios.
NEXT STEPS
  • Study the concept of vector quantities in physics.
  • Learn how to interpret distance-time graphs effectively.
  • Research the differences between average speed and average velocity.
  • Practice calculating displacement using various examples.
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Students studying physics, educators teaching motion concepts, and anyone looking to understand the differences between displacement, average speed, and average velocity.

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Okay so I don't understand how to do the displacement of distance and time on a graph. I also need help with figuring out the average speed and average velocity. The graph deals with a Turtle's journey.
On the Y-axis of the graph is distance in meters and the x-axis is time in minutes.
The y-axis goes from 1-23 and the x going by threes all the up to 66.
So the coordinates to the dots on the graph are the following: (3,2) (6,4) (12,6) (18,8) (24,10) (28,8) (30,7) (35,10) (40,12) (46,14) (51,14) (54,17) (57,20) (65,20) (66,23) *Also the total distance the turtle traveled was 29 m.

The following question's are:
1. What was the turtle's displacement?
2. What was the turtle's average speed?
3. What was the turtle's average velocity?



My answers so far:
1. 23-0=23 23/66= 2.9 m
2. 29/66=2.3 m
3. I don't even know where to begin for this one...
 
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Your first two answers are correct, except that you have the units wrong on one of them.
Displacement is a vector, velocity is a vector. Average velocity is displacement/time.
 

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