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Displacement of airplanes in opposite directions.

  1. Jul 30, 2010 #1
    An air traffic controller observes two airplanes approaching the airport. The displacement from the control tower to plane 1 is given by vector A, which has the magnitude 220km and points in a direction 32(degrees) north of west. The displacement from the control tower to plane 2 is given by the vector B, which has a magnitude of 140km and points 65(degrees) east of north. Find the magnitude and direction of vector C.

    I understand that it needs to be broken up into its components, but I am unable to get the answer (320km @ 10(degrees) north of west). Thanks for any help.
     
  2. jcsd
  3. Jul 30, 2010 #2

    Doc Al

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    What's vector C?
     
  4. Jul 30, 2010 #3
    C=A-B (the displacement from plane 2 to plane 1)
     
  5. Jul 30, 2010 #4

    Doc Al

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    Good. So what are the components of A and B? (Call East +x, and North +y)
     
  6. Jul 30, 2010 #5
    Ax= (-220km)cos32
    Ay= (220km)sin32
    Bx= (140km)cos65
    By=(140km)sin65
     
  7. Jul 30, 2010 #6

    Doc Al

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    OK.
    Careful: The angle here is given with respect to the North (y), not the East (x).
     
  8. Jul 30, 2010 #7
    Ahh yes, thank you! I have found the solution.
     
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