Displacement Using Tabular Reimann Sum

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SUMMARY

The discussion focuses on calculating displacement using the midpoint Riemann sum with 4 subintervals of equal width for a given set of velocity data. The initial calculation incorrectly used a delta x of 12, leading to an erroneous displacement of -12 feet. Upon reevaluation, the correct delta x is determined to be 24, which aligns with the 8 subintervals approach. This adjustment is crucial for accurately computing the displacement based on the provided velocity values.

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Homework Statement



Find the displacement using a midpoint Reimann sum with 4 subintervals of equal width.

minute 0, 12, 24, 36, 48, 60, 72, 84, 96
ft/min -4, -4, 1, 4, 5, -6, 0, 5, 2

Homework Equations



Displacement is the final position minus starting position.

The Attempt at a Solution



Reimann sum:

delta x = 12

12[-4 + 4 + -6 + 5] I'm choosing all the ft/min values at the midpoints (which are 12, 36, 60, and 84).

12[-1] = -12 feet.

This isn't the correct answer however.
 
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Qube said:

Homework Statement



Find the displacement using a midpoint Reimann sum with 4 subintervals of equal width.

minute 0, 12, 24, 36, 48, 60, 72, 84, 96
ft/min -4, -4, 1, 4, 5, -6, 0, 5, 2

Homework Equations



Displacement is the final position minus starting position.

The Attempt at a Solution



Reimann sum:

delta x = 12

12[-4 + 4 + -6 + 5] I'm choosing all the ft/min values at the midpoints (which are 12, 36, 60, and 84).

12[-1] = -12 feet.

This isn't the correct answer however.

Now why do you think Δx=12?
 
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Oops. I was thinking of a Reimann sum with 8 subintervals I suppose. Delta x is 24. That would make a lot more sense.
 

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