A mass m is moving at a speed of Vo and slides smoothly onto a sloped big block of mass M. The big block can also move on the table surface. Assume that everything moves without friction. After the small block reaches the height h on the slope It slides down. Find the height h. Problem Number 15-16 From: http://aapt.org/physicsteam/2010/upload/2010_FmaSolutions.pdf 2. Ug = mgh and KE = .5mVo^2 3. The attempt at a solution: .5(m+M)Vo ^ 2 = mgh solve for h = [(m+M)v^2]/(2mg) Which isn't the correct answer in the answer set, I am assuming I am factoring in how the big block moves into my equation wrong. How would I set this up to receive the answer given in the solution set? Thanks.