Distance and acceleration problem

  • Thread starter david_duhig
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In summary, the motorist must decelerate from 120 km/h to 57.6 m/s in order to avoid a speeding ticket.
  • #1
david_duhig
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Homework Statement


A police radar has an effective range of 1.0 km, and a motorist's radar detector has a range of 1.9 km. The motorist is going 120 km/h in a 80 km/h zone when the radar detector beeps. At what rate must the motorist decelerate to avoid a speeding ticket?

Homework Equations


v^2=u^2+2as
v=288m/s
u=432m/s
a=
t=
s=900m

The Attempt at a Solution


82944=186624+(2*a*900)

(82944-186624)/900/2

=57.6m/s^2
 
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  • #2
60 m.p.h.=88 ft/sec. Your velocities of 288 m/sec and 432 m/sec are much too high. 1 meter is slightly greater than 3 ft.
 
  • #3
Charles Link said:
60 m.p.h.=88 ft/sec. Your velocities of 288 m/sec and 432 m/sec are much too high. 1 meter is slightly greater than 3 ft.
Ahh of course, thank you for your help.
 
  • #4
david_duhig said:

Homework Equations


v^2=u^2+2as
v=288m/s
u=432m/s
a=
t=
s=900m

The Attempt at a Solution


82944=186624+(2*a*900)

(82944-186624)/900/2

=57.6m/s^2
check the calculation;
for example 80 km/h = 80 x 10^3 m/ (60x60) sec.= 800/36 m/s=200/9 m/s and you are writing v=288m/s so correct it and other velocity also.
 
  • #5
david_duhig said:

Homework Statement


A police radar has an effective range of 1.0 km, and a motorist's radar detector has a range of 1.9 km. The motorist is going 120 km/h in a 80 km/h zone when the radar detector beeps. At what rate must the motorist decelerate to avoid a speeding ticket?

Homework Equations


v^2=u^2+2as
v=288m/s
u=432m/s
Interesting fact: the speed of sound at sea level is about 340 m/s, also known as Mach 1.

If you're going Mach 1 in an 80 kph zone, no crummy Fuzz is going to catch you. o_O
 
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  • #6
drvrm said:
check the calculation;
for example 80 km/h = 80 x 10^3 m/ (60x60) sec.= 800/36 m/s=200/9 m/s and you are writing v=288m/s so correct it and other velocity also.
Thank you.
 

1. What is the formula for calculating distance and acceleration?

The formula for calculating distance and acceleration is d = 1/2at^2, where d is the distance, a is the acceleration, and t is the time.

2. How do you find the distance traveled with a given acceleration and time?

To find the distance traveled with a given acceleration and time, use the formula d = 1/2at^2 and plug in the values for acceleration and time. This will give you the distance traveled in that time period.

3. What is the difference between distance and displacement in relation to acceleration?

Distance refers to the total length traveled, while displacement refers to the change in position. In relation to acceleration, distance takes into account the entire path traveled, while displacement only considers the change in position caused by acceleration.

4. How does acceleration affect the distance an object travels?

Acceleration affects the distance an object travels by increasing or decreasing the speed at which the object is moving. The greater the acceleration, the greater the distance the object will travel in a given time period.

5. Can acceleration be negative?

Yes, acceleration can be negative. Negative acceleration, also known as deceleration, occurs when an object is slowing down. This can happen when the acceleration is in the opposite direction of the object's motion.

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