Distance and acceleration problem

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Homework Help Overview

The problem involves a motorist's speed and the necessary deceleration to avoid a speeding ticket, with specific parameters related to radar detection ranges and speed limits. The subject area includes kinematics and motion equations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the equation v² = u² + 2as, with attempts to calculate deceleration. There are questions regarding the accuracy of the initial velocity values provided by the original poster, as they appear to be significantly high.

Discussion Status

Some participants have pointed out potential errors in the velocity conversions and calculations. There is ongoing clarification regarding the correct values to use, but no consensus has been reached on the final approach to the problem.

Contextual Notes

Participants are addressing discrepancies in unit conversions and the implications of using incorrect values in the kinematic equations. The original poster's calculations are being scrutinized for accuracy.

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Homework Statement


A police radar has an effective range of 1.0 km, and a motorist's radar detector has a range of 1.9 km. The motorist is going 120 km/h in a 80 km/h zone when the radar detector beeps. At what rate must the motorist decelerate to avoid a speeding ticket?

Homework Equations


v^2=u^2+2as
v=288m/s
u=432m/s
a=
t=
s=900m

The Attempt at a Solution


82944=186624+(2*a*900)

(82944-186624)/900/2

=57.6m/s^2
 
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60 m.p.h.=88 ft/sec. Your velocities of 288 m/sec and 432 m/sec are much too high. 1 meter is slightly greater than 3 ft.
 
Charles Link said:
60 m.p.h.=88 ft/sec. Your velocities of 288 m/sec and 432 m/sec are much too high. 1 meter is slightly greater than 3 ft.
Ahh of course, thank you for your help.
 
david_duhig said:

Homework Equations


v^2=u^2+2as
v=288m/s
u=432m/s
a=
t=
s=900m

The Attempt at a Solution


82944=186624+(2*a*900)

(82944-186624)/900/2

=57.6m/s^2
check the calculation;
for example 80 km/h = 80 x 10^3 m/ (60x60) sec.= 800/36 m/s=200/9 m/s and you are writing v=288m/s so correct it and other velocity also.
 
david_duhig said:

Homework Statement


A police radar has an effective range of 1.0 km, and a motorist's radar detector has a range of 1.9 km. The motorist is going 120 km/h in a 80 km/h zone when the radar detector beeps. At what rate must the motorist decelerate to avoid a speeding ticket?

Homework Equations


v^2=u^2+2as
v=288m/s
u=432m/s
Interesting fact: the speed of sound at sea level is about 340 m/s, also known as Mach 1.

If you're going Mach 1 in an 80 kph zone, no crummy Fuzz is going to catch you. o_O
 
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drvrm said:
check the calculation;
for example 80 km/h = 80 x 10^3 m/ (60x60) sec.= 800/36 m/s=200/9 m/s and you are writing v=288m/s so correct it and other velocity also.
Thank you.
 

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