How do I find the distance between two lines passing through different points?

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SUMMARY

The discussion focuses on calculating the distance between two skew lines defined by points A(2,1,2), B(3,2,-1) and C(-1,2,4), D(-2,1,3). The lines are determined to be skew after checking their parallelism. The key steps involve calculating the direction vectors AB and CD, using the vector product to find a normal vector N, and applying vector projection to determine the shortest distance between the two lines. Visual representation is emphasized as a crucial step in understanding the spatial relationship between the lines.

PREREQUISITES
  • Understanding of vector operations, including dot product and cross product
  • Familiarity with vector equations of lines in three-dimensional space
  • Knowledge of unit vectors and their applications in distance calculations
  • Ability to visualize geometric relationships in three dimensions
NEXT STEPS
  • Study the method for calculating the shortest distance between two skew lines
  • Learn about vector projection techniques in three-dimensional geometry
  • Explore the application of the vector product in determining normal vectors
  • Practice visualizing three-dimensional geometric configurations using software tools
USEFUL FOR

Students in mathematics or physics, particularly those studying vector calculus and geometry, as well as educators looking for effective teaching strategies for spatial reasoning.

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Homework Statement



Okay thanks everyone for taking the time to read this quesiton. Now I sort of know how to do this question but I am not entirely sure how I should approach it:

I have points A(2,1,2) B(3,2,-1) C(-1,2,4) and D(-2,1,3)

Now a line passes through points A and B and also C and D respectively. What essentially we need to find is that the line that passes through A and B is at least 1 metre apart from the line that passes through C and D

Homework Equations



Dot Product, cross product. unit vector, shortest distance between two points*

The Attempt at a Solution


[/B]
So in order for there to be a distance we must check if the lines are parallel or not...
After conducting a test I found that these lines are skewed.

What I am confused about is this. I have 4 sets of coordinates now I know if I do

AB = B - A = (1,1,-1)

and CD = D - C = (-1,-1,-1) I get two vector equations

Now to find the distance between two vector equations we use vector projection and the unit vector but I am not sure how I can lay that out
 
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So you have two lines ##\vec A + \lambda(\vec B - \vec A)## and ##\vec C + \mu (\vec D - \vec C)##.
If I follow this example I need the veector product ##\vec N = \vec {AB} \times \vec {CD}## as the main step.

And note their extremely important tip: make a picture to see what you are doing !
 

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