Distance between the object and the lens

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Homework Help Overview

The discussion revolves around a problem involving a diverging lens with a focal length of 6 mm and an image magnification of 1/2. Participants are tasked with determining the distance between the object and the lens.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss relevant equations that relate object size to image size, including the magnification formula and the lens formula. There is a focus on identifying the correct relationships and variables involved.

Discussion Status

Participants are actively engaging with the problem, sharing hints and equations. Some have identified that they have two equations with two unknowns, prompting further exploration of how to manipulate these equations to find the desired distance.

Contextual Notes

There is a mention of uncertainty regarding the image distance, which is a critical variable needed to solve for the object distance. The discussion reflects the constraints of working with incomplete information.

Libra_girl
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Homework Statement



A diverging lens of 6 mm focal length produces an image of magnification m = 1/2. What
is the distance between the object and the lens?
 
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Welcome to PF!

Libra_girl said:

Homework Statement



A diverging lens of 6 mm focal length produces an image of magnification m = 1/2. What
is the distance between the object and the lens?

Hi Libra_girl ! Welcome to PF! :smile:

Hint: what equations do you know that relate the size of the object to the size of the image? :smile:
 
tiny-tim said:
Hi Libra_girl ! Welcome to PF! :smile:

Hint: what equations do you know that relate the size of the object to the size of the image? :smile:


Is it the equation: do/di = m or 1/do + 1/di = 1/f ?
 
Libra_girl said:
Is it the equation: do/di = m or 1/do + 1/di = 1/f ?

Both equations! :smile:

Except isn't it m = -di/do? :rolleyes:
 
tiny-tim said:
Both equations! :smile:

Except isn't it m = -di/do? :rolleyes:


yeah it is sorry :smile:
 
Last edited:
Libra_girl said:
yeah it is sorry :smile:

tiny-tim said:
Both equations! :smile:

Except isn't it m = -di/do? :rolleyes:

Ok so I know f and I know m, now I am solving for do, but I don't know the di?
 
Hi Libra girl,

You now have two equations in two unknowns. You can solve the magnification formula for one of the variables and plug it into the other formula. What does that give?
 

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