Distance Rolled by 2.2cm Coin in 9.034s

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Homework Help Overview

The discussion revolves around the distance a coin rolls based on its radius and time of rolling, as well as a related scenario involving angular motion and kinematics. The subject area includes concepts from rotational dynamics and linear motion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationship between the radius of the coin, time, and the distance rolled, questioning the need for speed to determine the distance. Others introduce concepts from rotational kinematics, discussing angular speed and acceleration.

Discussion Status

Some participants have offered insights into the equations of motion relevant to the problem, while others are questioning the completeness of the information provided, particularly regarding the speed of the coin. Multiple interpretations of the problem are being explored.

Contextual Notes

There is a lack of explicit information regarding the speed of the coin in the initial scenario, which is crucial for calculating the distance rolled. Additionally, the discussion includes assumptions about the nature of the motion (e.g., rolling without slipping).

starfish794
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If a coin with a radius of 2.2cm rolls for 9.034s, how far does it roll?

The answer needs to be in meters so 2.2cm=.022m. Is there a simple formula for this? I feel like I'm missing something easy.
 
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starfish794 said:
If a coin with a radius of 2.2cm rolls for 9.034s, how far does it roll?

The answer needs to be in meters so 2.2cm=.022m. Is there a simple formula for this? I feel like I'm missing something easy.
Something is missing. You need to know the speed of the coin to answer this question.
 
A coin with a diameter of 2.20 cm is dropped on edge onto a horizontal surface. The coin starts out with an initial angular speed of 15.9 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular acceleration of magnitude 1.76 rad/s2, how far does the coin roll before coming to rest?

That was the original question and then i used w=w+(alpha)t to find the time.
 
starfish794 said:
A coin with a diameter of 2.20 cm is dropped on edge onto a horizontal surface. The coin starts out with an initial angular speed of 15.9 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular acceleration of magnitude 1.76 rad/s2, how far does the coin roll before coming to rest?

That was the original question and then i used w=w+(alpha)t to find the time.
Use the other equations of rotational kinematics (w=w+(alpha)t is just one of this set of equations) to find the angular displacement of the coin during this time interval. Then figure out how far a point on the circumference of the coin would have moved if the coin had just been rotating about its center. Since the coin was not slipping, this is the distance the coin moved before coming to a stop. In one rotation, the coin moves one circumference.
 

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