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Homework Help: Distance travelled in n time when a body is thrown upwards

  1. Apr 28, 2014 #1
    1. The problem statement, all variables and given/known data
    Here is a question in my text book. I saw the answer, but no explanation was there.

    A stone is thrown vertically upward with an initial velocity [itex]v_0[/itex]. The distance travelled by it in time [itex]\frac{1.5v_0}{g}[/itex] is ______________.
    Answer is [itex]\frac{5v_0^2}{8g}[/itex].

    2. Relevant equations
    Max. height reached by a body thrown upwards with an initial velocity v is [itex]\frac{v^2}{2g}[/itex]
    Time taken to reach the max.height with initial velocity v=[itex]\frac{v}{g}[/itex]

    3. The attempt at a solution

    Time taken to travel AB+BC=[itex]\frac{1.5v_0}{g}[/itex]

    We know that time taken to travel AB=[itex]\frac{v_0}{g}[/itex]

    ∴Time taken to travel BC=[itex]\frac{1.5v_0}{g} - \frac{v_0}{g}[/itex]

    Initial velocity at B in BC=u=0


    We know [itex]v=u+at[/itex]






    Distance of AB+BC=[itex]\frac{v_0^2}{2g}+\frac{v_0^2}{8g}[/itex]

  2. jcsd
  3. Apr 28, 2014 #2
    man you made a slight arithmetic mistake in the last line.
  4. Apr 28, 2014 #3
    Oh yes! Thanks. I am happy at least I made only arithmetic mistake and not a concept mistake.
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