Distance under constant acceleration

[Alpha[X]²]

A body starts from rest with an acceleration of 11m/s².

What is it's velocity after 6 seconds. (I got 66 for that) and how far did it travel?

What formula do I have to use for this?

 

[radou]

There is a well-known expression which represents displacement under constant acceleration. Try to find it. (Either here or google it up.)

 

[Alpha[X]²]

Is displacement the same as distance?

 

[radou]

Is displacement the same as distance?

Yes it is, in this case.

 

[Alpha[X]²]

What about the first part of the question?

I tried to average out the velocity and then using the d=vt formula I got 198m.

 

[Zeno's Paradox]

What about the first part of the question?

I tried to average out the velocity and then using the d=vt formula I got 198m.

Yes, you did it correctly. Remember that you could calculate the displacement averaging out the velocity only because the acceleration is constant.

The other formula would be: d = (1/2)at². Check that the solution is the same.

Try to show that v(average)*t = (1/2)at²