Distance under constant acceleration

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Homework Help Overview

The discussion revolves around a problem involving a body starting from rest and accelerating at a constant rate of 11 m/s². Participants are exploring the relationship between velocity, displacement, and the relevant formulas to calculate these quantities over a specified time period of 6 seconds.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the velocity after 6 seconds and the distance traveled, seeking the appropriate formula. Some participants suggest looking for a known expression for displacement under constant acceleration. There is also a question raised about the distinction between displacement and distance.

Discussion Status

The discussion is active, with participants providing insights and confirming calculations. Some guidance has been offered regarding the use of formulas for displacement, and there is an acknowledgment of the relationship between average velocity and displacement under constant acceleration.

Contextual Notes

Participants are navigating the definitions of displacement and distance, with some asserting they are equivalent in this context. There is a focus on ensuring the correct application of formulas given the conditions of constant acceleration.

Alpha[X]²
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A body starts from rest with an acceleration of 11m/s².

What is it's velocity after 6 seconds. (I got 66 for that) and how far did it travel?

What formula do I have to use for this?
 
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There is a well-known expression which represents displacement under constant acceleration. Try to find it. (Either here or google it up.)
 
Is displacement the same as distance?
 
Alpha[X]² said:
Is displacement the same as distance?

Yes it is, in this case.
 
What about the first part of the question?

I tried to average out the velocity and then using the d=vt formula I got 198m.
 
Alpha[X]² said:
What about the first part of the question?

I tried to average out the velocity and then using the d=vt formula I got 198m.

Yes, you did it correctly. Remember that you could calculate the displacement averaging out the velocity only because the acceleration is constant.

The other formula would be: d = (1/2)at2. Check that the solution is the same.

Try to show that v(average)*t = (1/2)at2
 
Last edited:

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