Distributing Presents Among Children

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SUMMARY

The problem of distributing 15 identical gifts among 10 distinct children can be solved using the stars and bars combinatorial method. The correct formula is given by the binomial coefficient (n + k - 1, k - 1), where n is the number of gifts (15) and k is the number of children (10). This results in the calculation (24, 9) = 24!/(9!*15!). An alternative approach involves summing the binomial coefficients (15 0) + (15 1) + (15 2) + ... + (15 10), which accounts for all possible distributions of gifts among the children.

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Homework Statement



in how many ways can one distribute 15 identical gifts between 10 distinct children?


Homework Equations



(n + k - 1, k - 1) bionomail coeff.

The Attempt at a Solution



n = 15, k = 10

(24, 9) = 24!/(9!*15!)

It would be much appreciated if someone can verify my result. Thanks.
 
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I don't think what you have is right. I think the total number of ways is the sum of the binomial coefficients
(15 0) + (15 1) + (15 2) + ... + (15 10) where each one is n!/[(n - k)! k!]

My reasoning is this:
(15 0) - the number of ways to give all 15 gifts to no one--1 way
(15 1) - the number of ways to give all 15 gifts to 1 child--15 ways
(15 2) - the number of ways to give 15 gifts to 2 children (and hence none to the other 8)
And so on.
Anyway, that's how I would approach this problem.
 

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