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Distribution of particle energy in 3He fusion

  1. May 16, 2010 #1
    The 3He-3He fuel cycle releases protons and alpha particles, plus 12.9 MeV of energy. No matter where I look, I can't find any information about how that 12.9 MeV is distributed over the fusion products, every source just quotes the 12.9 total.

    Does anyone know how this energy tends to be distributed, or can show me how to derive it (I'm sure there must be an equation, but I'm only a beginner at this, so I can't guess at what it is).
  2. jcsd
  3. May 17, 2010 #2
    write down the total reaction
  4. May 17, 2010 #3
    3He + 3He -> 2p + 4He + 12.85 MeV ?
  5. May 17, 2010 #4
    3 bodies in the final state means that they all have a contunous energu spectra
  6. May 17, 2010 #5
    Huh, okay then.
  7. May 18, 2010 #6
    just as in beta decay for instance, basic kinematics
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