Divergence Simplification/Identities

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Discussion Overview

The discussion revolves around the simplification of the expression \nabla\bullet (a \bullet b)b, where a and b are vectors. Participants explore potential identities and methods for rewriting the expression, including the application of vector calculus identities.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant asks about the simplification of \nabla\bullet (a \bullet b)b and whether it can be expressed differently.
  • Another participant introduces the general identity \nabla (\varphi \mathbf{F})=(\nabla \varphi)\bullet\mathbf{F}+\varphi (\nabla \bullet \mathbf{F}) and suggests substituting \varphi = \mathbf{a}\bullet \mathbf{b} and \mathbf{F}=\mathbf{b}.
  • A participant expresses uncertainty about the equivalence of \nabla\bullet (\mathbf{a} \bullet \mathbf{b})\mathbf{b} and \nabla (\varphi \mathbf{F}), questioning the presence of the dot product between \nabla and the rest of the expression.
  • Another participant corrects a previous statement regarding the identity, clarifying that it should be \nabla \bullet (\varphi \mathbf{F}) instead.
  • One participant mentions that substituting into the equation may lead to a more complex expression but is looking for a simpler approach.
  • Another participant suggests using the gradient of the vector dot product for simplification and mentions the Levi-Civita tensor as a potential tool for further simplification.

Areas of Agreement / Disagreement

The discussion includes multiple competing views on how to simplify the expression, and participants express uncertainty about the equivalence of different forms. No consensus is reached on a definitive simplification method.

Contextual Notes

Participants note that the simplifications may lead to complex expressions and that certain identities may not be straightforward to apply without additional context or assumptions.

feedmeister
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Quick question…

what does the following simplify to? Can it be written in any other way?

\nabla\bullet (a \bullet b)b

where a and b are vectors.

Thanks,
 
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feedmeister said:
Quick question…

what does the following simplify to? Can it be written in any other way?

\nabla\bullet (a \bullet b)b

where a and b are vectors.

Thanks,

in general

\nabla (\varphi \mathbf{F})=(\nabla \varphi)\bullet\mathbf{F}+\varphi (\nabla \bullet \mathbf{F})

let \varphi = \mathbf{a}\bullet \mathbf{b}

and \mathbf{F}=\mathbf{b}
 
IssacNewton said:
in general

\nabla (\varphi \mathbf{F})=(\nabla \varphi)\bullet\mathbf{F}+\varphi (\nabla \bullet \mathbf{F})

let \varphi = \mathbf{a}\bullet \mathbf{b}

and \mathbf{F}=\mathbf{b}

Thanks, but I didn't think that \nabla\bullet (\mathbf{a} \bullet \mathbf{b})\mathbf{b} was the same as \nabla (\varphi \mathbf{F})... there's still a \bullet between the \nabla and the rest of the statement.

Can you clarify?
 
IssacNewton said:
in general

\nabla (\varphi \mathbf{F})=(\nabla \varphi)\bullet\mathbf{F}+\varphi (\nabla \bullet \mathbf{F})

little mishtake...above should be

\nabla \bullet (\varphi \mathbf{F})=(\nabla \varphi)\bullet\mathbf{F}+\varphi (\nabla \bullet \mathbf{F})

:-p
 
Thanks, IssacNewton.

When substituting in \mathbf{a}\bullet \mathbf{b} and \mathbf{b} into the equation, it looks like it'd simplifies further.. but it looks like it'd be ugly.

Any good way of simplifying it?

Thanks,
 

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