Divided by highest term in numerator limit

  • Thread starter Thread starter whatlifeforme
  • Start date Start date
  • Tags Tags
    Limit Term
Click For Summary
SUMMARY

The limit evaluation of the expression limx→∞ (2x - 3x) / (3x + 4x) results in zero when divided by the highest term in the numerator, specifically 3x. The correct approach involves rewriting the limit as limx→∞ ((2/3)x - 1) / (1 + (4/3)x), which clearly approaches zero as x approaches infinity. This method contrasts with the incorrect approach of dividing by the highest term in the denominator, which does not yield the correct result.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with exponential functions
  • Knowledge of asymptotic behavior of functions
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study the properties of limits involving exponential functions
  • Learn about L'Hôpital's Rule for evaluating indeterminate forms
  • Explore the concept of dominant terms in limits
  • Practice similar limit problems to reinforce understanding
USEFUL FOR

Students studying calculus, particularly those focusing on limits and exponential functions, as well as educators seeking to clarify limit evaluation techniques.

whatlifeforme
Messages
218
Reaction score
0

Homework Statement


evaluate.

Homework Equations


lim[itex]\displaystyle _{x->∞} \frac{2^x - 3^x}{3^x + 4^x}[/itex]

The Attempt at a Solution


i tried diving by highest term in denominator (4^x), but got me no where.

the solution manual has: (divided by highest term in numerator.)with the answer is zero which i don't know how.

lim[itex]_{x->∞}\displaystyle \frac{(\frac{2}{3})^x - 1}{1 + (\frac{4}{3})^x}[/itex] = 0
 
Physics news on Phys.org
whatlifeforme said:

Homework Statement


evaluate.


Homework Equations


lim[itex]\displaystyle _{x->∞} \frac{2^x - 3^x}{3^x + 4^x}[/itex]


The Attempt at a Solution


i tried diving by highest term in denominator (4^x), but got me no where.

the solution manual has: (divided by highest term in numerator.)with the answer is zero which i don't know how.

lim[itex]_{x->∞}\displaystyle \frac{\frac{2^x}{3^x} - 1}{1 + \frac{4^x}{3^x}}[/itex] = 0

Factor 3x out of the numerator and factor 4x out of the denominator.
 
whatlifeforme said:

Homework Statement


evaluate.


Homework Equations


lim[itex]\displaystyle _{x->∞} \frac{2^x - 3^x}{3^x + 4^x}[/itex]


The Attempt at a Solution


i tried diving by highest term in denominator (4^x), but got me no where.

the solution manual has: (divided by highest term in numerator.)with the answer is zero which i don't know how.

lim[itex]_{x->∞}\displaystyle \frac{\frac{2^x}{3^x} - 1}{1 + \frac{4^x}{3^x}}[/itex] = 0

Why didn't dividing by 4^x get you anywhere?
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
7
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
17
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 34 ·
2
Replies
34
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K