Dividing differential equations

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SUMMARY

The discussion focuses on dividing second-order differential equations to derive an expression for X(T) from two equations: eqn1: \(\frac{d^{2}X}{da^{2}} = -X \left(\frac{dT}{da}\right) \left(\frac{dT}{da}\right)\) and eqn2: \(\frac{d^{2}T}{da^{2}} = \frac{-2}{X^{2}} \left(\frac{dX}{da}\right) \left(\frac{dT}{da}\right)\). The user successfully simplifies the second-order derivatives by recognizing that the operator \(d/da\) cancels when dividing the equations. The final result obtained is X(T) = exp(T/sqrt(2)).

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  • Understanding of second-order differential equations
  • Familiarity with differentiation and the operator notation
  • Knowledge of exponential functions and their properties
  • Basic algebraic manipulation skills
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  • Study the method of solving second-order differential equations
  • Learn about the application of differential operators in calculus
  • Explore the relationship between first and second derivatives
  • Investigate the use of exponential functions in differential equations
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Students studying differential equations, mathematicians, and anyone interested in advanced calculus techniques for solving complex equations.

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Homework Statement



This is more of a problem I have with my knowledge of differentials. I have two second order differential equations for variables X(a) and T(a). I want to get an expression for X(T). I know I have to divide them, but how do you go about dividing them if they are explicitly stated as:

eqn1: \frac{d^{2}X}{da^{2}} = Some polynomial

and,

eqn2: \frac{d^{2}T}{da^{2}} = Some polynomial

The Attempt at a Solution



I know for first derivative with respect to 'a', you can just divide them directly and the 'da' part will just cancel, but what would you get for a second derivative?

Example of first derivative would be:

dX/da divided by dT/da would equal dX/dT, and you could just solve the resulting simple differential equation to get X(T).
 
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Ok, maybe I should give the RHS of the equations too..


eqn1: \frac{d^{2}X}{da^{2}} = -X \frac{dT}{da}} \frac{dT}{da}}

eqn2: \frac{d^{2}T}{da^{2}} = \frac{-2}{X^{2}} \frac{dX}{da}} \frac{dT}{da}}
 
Never mind, I'm retarded. I just expressed the second order derivative as :

d/da(dX/da) and when you divide it by d/da(dT/da) the d/da part cancels because its just like an operator. I got an exponential result as X(T) = exp(T/sqrt(2))
 

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