Do you understand what linearization means?

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Homework Help Overview

The discussion revolves around the concept of linearization in the context of a differential equation involving variables x and y. The original poster presents a nonlinear equation and seeks clarification on how to approach the problem, particularly in relation to linear approximations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the process of linearization, suggesting the replacement of nonlinear functions with linear approximations. There is mention of using Taylor series for this purpose. Some participants question the interpretation of the variables and their dependencies.

Discussion Status

The conversation includes various attempts to clarify the concept of linearization, with some participants providing insights into the use of Taylor series. However, there is no explicit consensus on the approach to take, and multiple interpretations of the problem are being explored.

Contextual Notes

There are indications of confusion regarding the equations presented and the initial conditions. Some participants express frustration over incomplete communication, which may hinder the discussion.

hihi
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do you understand what "linearization" means?

Homework Statement



Linearization
4x'' + 3 cos(x-y)y'' +2 y^2 sin(x-y) +3g sin (x) = 0

Homework Equations



initial condition x(0) = y(0) = 0


The Attempt at a Solution



pls tell me the relevant steps to solve this problem.thanx
 
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Do you understand what "linearization" means? (I ask because I finally realized how simple it was the day after a test!)

Just replace any non-linear functions of the dependent variable by linear approximations.

It would help, of course, to separate dependence on the different variables (am I correct that both x and y are dependent variables, depending on a third variable and the derivatives are with respect to that third variable?): using the trig sum formulas cos(x- y)= cos(x)cos(y)+ sin(x)sin(y) and sin(x-y)= sin(x)cos(y)- cos(x)sin(y). Since you will want to approximate around x= y= 0, the linear approximation to sin(x) is x near x= 0 and to cos(x) is 1 around x= 0. (You can see that by looking at their Taylor's series.) Of coure, the only "linear" approximation to y2 or xy around y= 0 is 0.
 
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x'' means diferentiation twice.however, i think it should be solve by using taylor series.Am i correct??But i still can do it...
 
My only point about Taylor's series is that by dropping all the terms of degree 2 or above, you get the "linearization".
sin(x)= x- x3/3!+ ... and so the "linearization" of sin(x), around x= 0, is x.
cos(x)= 1- x2/2!+... so the "linearization" of cos(x), around 0, is 1.
 
sorry,there is another equation given which is 3 cos(x-y) y'' + 2y'' - 2y' ^2 sin(x-y) +g sin(y) =0 .

but,the answer for this question is 4x'' + 3y'' + 3g x = 0 and 3x'' + 2y'' + gy = 0.

pls help...
 
If you can't be bothered to type in complete sentences, and clearly state your point of confusion, why should somebody take the time to explain anything to you?

I really don't get why people do this.
 
1. Homework Statement

Linearization

4x'' + 3 cos(x-y)y'' +2 y^2 sin(x-y) +3g sin (x) = 0

3 cos(x-y) y'' + 2y'' - 2y' ^2 sin(x-y) +g sin(y) =0
2. Homework Equations

initial condition x(0) = y(0) = 03. The Attempt at a Solution

the answer for this question is 4x'' + 3y'' + 3g x = 0 and 3x'' + 2y'' + gy = 0.

pls tell me the relevant steps to solve this problem.thanx
 
pls help...thanx
 
hihi said:
sorry,there is another equation given which is 3 cos(x-y) y'' + 2y'' - 2y' ^2 sin(x-y) +g sin(y) =0 .

but,the answer for this question is 4x'' + 3y'' + 3g x = 0 and 3x'' + 2y'' + gy = 0.

pls help...
?? Are you saying that you started with two equations:
4x'' + 3 cos(x-y)y'' +2 y^2 sin(x-y) +3g sin (x) = 0
and
3 cos(x-y) y'' + 2y'' - 2y' ^2 sin(x-y) +g sin(y) =0 .

And it didn't occur to you to tell us that?
 

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