Does a Magnetic Field Emerge from a Moving Charge with Constant Angular Speed?

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SUMMARY

The discussion centers on whether a magnetic field emerges from a moving charge with constant angular speed. Participants assert that circular motion of a charge necessitates a centripetal force, implying the presence of a magnetic field. A charged pith ball on a rotating disk is suggested as a practical example. The mathematical representation of the magnetic field is provided, indicating that a magnetic field exists in the far field, characterized by the equation ##B_z(r,\theta) = (1/r^2 sin \theta) cos(\omega t +f(\rho,t))##, alongside a perpendicular electric field.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with classical electrodynamics
  • Knowledge of centripetal acceleration and circular motion
  • Basic grasp of electromagnetic field equations
NEXT STEPS
  • Study the Lagrangian formulation for charged particles in electromagnetic fields
  • Learn about synchrotron radiation and its implications in classical electrodynamics
  • Review Landau and Lifshitz's "Classical Electrodynamics" for advanced concepts
  • Examine Jackson's "Classical Electrodynamics" for detailed field equations of moving charges
USEFUL FOR

Physicists, electrical engineers, and students studying classical mechanics and electromagnetism, particularly those interested in the behavior of charged particles in motion.

Timothy S
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If I write the lagrangian for a moving charge with constant angular speed, would a magnetic field be emergent? I would do the math myself, but I'm nowhere near pen and paper.
 
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Timothy S said:
If I write the lagrangian for a moving charge with constant angular speed, would a magnetic field be emergent? I would do the math myself, but I'm nowhere near pen and paper.
First of all, if there is no magnetic field to begin with why would a charge spin in circles? Spinning in circles implies there is some kind of force, because there is a centripetal acceleration, without centripetal acceleration there is no circular motion.
 
Alexandre said:
First of all, if there is no magnetic field to begin with why would a charge spin in circles? Spinning in circles implies there is some kind of force, because there is a centripetal acceleration, without centripetal acceleration there is no circular motion.

A charged pith ball on the edge of a rotating disk, driven at constant angular velocity, would suffice.
 
stedwards said:
A charged pith ball on the edge of a rotating disk, driven at constant angular velocity, would suffice.
I think you need to solve for potential field and coordinate of the particle. But I'm not sure how, check this out
https://people.ifm.liu.se/irina/teaching/sem4.pdf
 
Alexandre said:
I think you need to solve for potential field and coordinate of the particle. But I'm not sure how, check this out
https://people.ifm.liu.se/irina/teaching/sem4.pdf

For whatever reason, that solution seems to leave out the fields generated by the accelerating charge, though I only scanned the paper. There should be a magnetic field in the far field having an intensity something like ##B_z(r,\theta) = (1/r^2 sin \theta) cos(\omega t +f(\rho,t))##, in standard spherical coordinates, accompanied by a perpendicular electric field.
 
I'm not sure, what the question is about. If you have given the motion of a charge, maybe you want to know the electromagnetic field due to this moving charge. You find this problem for circular motion in almost any textbook on classical electrodynamics. Look for synchrotron radiation. A good treatment can be found in Landau/Lifshitz vol. II and, of course, Jackson, Classical Electrodynamics.
 
Sorry it was a really stupid question on so many levels.
 

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