Does a sling or a gun exert more initial force of the projectile?

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Discussion Overview

The discussion centers on comparing the initial force exerted by a sling versus a gun when launching projectiles. Participants explore the kinetic energy and impulse associated with each method of propulsion, considering specific examples of a sling and a .22 caliber bullet.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant describes their experience with a sling that can launch a limestone rock weighing about 2 ounces, questioning whether it takes more force to shoot the rock or a bullet.
  • Another participant provides figures for the kinetic energy of a .22 caliber bullet, stating it is approximately 160 Joules, and compares it to a world record for slingshot projectiles at 113 Joules.
  • A different participant calculates the energy of their stone at 51 Joules and a .22 CB round at 45 Joules, suggesting a comparison of energies.
  • One participant argues that while the bullet has more kinetic energy, it does not necessarily require more impulse than the sling stone, emphasizing the difference between kinetic energy and momentum.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between kinetic energy and impulse, with some asserting that a bullet has more kinetic energy while others challenge the notion that this equates to greater impulse. The discussion remains unresolved regarding the comparison of forces exerted by the two methods.

Contextual Notes

Participants rely on specific measurements and calculations, but there are uncertainties regarding the exact weights and conditions of the projectiles discussed. The definitions of impulse and kinetic energy are also points of contention.

Allenph
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First of all this is probably the only time I will be on this forum.

At first this seems a no brainer. But I am a weekend survivalist and I made a sling that can sling rock a little more then 1" in diameter 120 yards at an angle of about 50-55 degrees. After some research the type of rock I am flinging is limestone which means it weighs about 2 ounces. Let's use say, a .22 caliber bullet. The bullet would weigh a little less then .09 ounces and go around 175 yards at 90 degrees. I have NO idea how to figure this out and am curious to know the answer. So does it take more force to shoot the rock or shoot a bullet?
 
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It's kind of important to know an accurate weight for the rock you used if you want to calculate the impulse required to accelerate it. Looking up the weight of a similar small rock won't do.

Instead, let's find some figures from the internet to use. The muzzle energy of an average .22 LR pistol is about 160 Joules, according to the wikipedia entry below. This means that the bullet leaves the muzzle of the gun with 160 Joules of kinetic energy.
http://en.wikipedia.org/wiki/Muzzle_energy

In the following video, they claim that the world record kinetic energy for a handheld slingshot projectile is 113 Joules. This is less energy than a .22 bullet, and chances are you're firing them off with quite a bit less energy than the world record holder.
http://youtu.be/1v4TEX2erog

So, in short, a projectile from a handgun has more kinetic energy (and requires a greater impulse) than a projectile from a handheld slingshot.
 
Excellent thanks for answering my question
 
I learned the math. My stone has 51 joules and a .22 CB round has 10% less at 45 Joules.
 
Nessdude14 said:
So, in short, a projectile from a handgun has more kinetic energy (and requires a greater impulse) than a projectile from a handheld slingshot.

More kinetic energy, yes. More impulse -- I don't think so.

The kinetic energy of a projectile scales as the square of its speed. The momentum of a projectile scales linearly with its speed. That means that a fast-travelling .22 slug has lots of kinetic energy but relatively little momentum compared to a slow-travelling sling stone.

"Impulse" is a measure of momentum, not energy.
 

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