The discussion centers on the physics of weight variation experienced by a student in an elevator. Initially, the student measures a weight of 840 N at rest. As the elevator ascends, the weight increases to 1050 N, indicating upward acceleration. When the elevator decelerates, the weight drops to 588 N, reflecting downward acceleration. The net force equations, F_net = ma, are crucial for calculating the acceleration during these phases.
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As the elevator rises or slowstennisacerg said:A student, standing on a scale in an elevator at rest, sees that his weight is 840 N. As the elevator rises, his weight increases to 1050 N, then returns to normal. When the elevator slows to a stop, his weight drops to 588 N. Determine the acceleration at the beginning and end of the trip.
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