Does an Orthogonal Transformation Preserve Subspace Dimension?

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SUMMARY

An orthogonal transformation T from R^n to R^n preserves the dimension of a subspace W of R^n. If the dimension of W is k, then the dimension of T(W) is also k. This is established by the fact that if {w_1,...,w_k} is an orthonormal basis for W, then the transformed set {Tw_1,...,Tw_k} remains linearly independent, confirming that dim T(W) = k. This property holds true for any invertible transformation, not just orthogonal ones.

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daniel_i_l
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Homework Statement


I have a general question. If we have some subspace W of R^n where dimW=k. Then if T is an orthogonal transformation from R^n->R^n is the dimension of T(W) also k?


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The Attempt at a Solution



The reason I think this is true is because if {w_1,...,w_k} is an orthonormal basis of W and {w_1,...,w_k,w_(k+1),...,w_n} is an orthonormal basis of R^n then {Tw_1,...,Tw_k,Tw_(k+1),...,Tw_n} Is also an orthonomal basis of R^n. But T(W)=Sp({Tw_1,...,Tw_k}) and if {Tw_1,...,Tw_k,Tw_(k+1),...,Tw_n} is an orthonormal basis then {Tw_1,...,Tw_k} are linearly independent and dimT(W) = k.

Is this true?
Thanks.
 
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Yes, and it's true more generally for any invertible transformation.
 

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