"Notice that these transformations do not alter the chirality of particles. A left-handed neutrino would be taken by charge conjugation into a left-handed antineutrino, which does not interact in the Standard Model." --https://en.wikipedia.org/wiki/C-symmetry The excerpt above seems to unambiguously answer this question. But, then: "You can easily convince yourself (exercise II.1.9) that the charge conjugate of a left handed field is right handed and vice versa." --Quantum Field Theory in a Nutshell, A. Zee These statements appear to be contradictory. What's going on here? Also, it does seem easy to convince myself of Zee's comment (following Zee's convention that [itex]\psi \to \psi_c = \gamma^2 \psi^\ast[/itex]): Suppose [itex]\psi[/itex] is left-handed (i.e. [itex]P_L \psi = \psi[/itex] and [itex]P_R \psi = 0[/itex]), then [tex]P_L \psi_c = P_L \gamma^2 \psi^\ast = \gamma^2 P_R \psi^\ast = \gamma^2 (P_R \psi)^\ast = 0[/tex] and [tex]P_R \psi_c = P_R \gamma^2 \psi^\ast = \gamma^2 P_L \psi^\ast = \gamma^2 (P_L \psi)^\ast = \psi_c[/tex] Therefore, it appears that Zee's comment is correct. Can anyone help me understand why the two quotes above are or are not in contradiction?