Does Earth's Gravity Do Work on Satellites?

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In a perfect circular orbit, Earth's gravity does not do work on satellites because the gravitational force is always perpendicular to the displacement of the satellite. This perpendicular relationship means that the dot product of the gravitational force and the displacement vector is zero, resulting in no work being done. Since both potential and kinetic energy remain constant in such an orbit, there is no energy transfer involved. Therefore, the conclusion is that gravity does not perform work on satellites in a stable circular orbit. Understanding this concept is crucial for analyzing orbital mechanics.
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Does the gravity of Earth do any work on satellites orbiting the planet, assuming perfect circular orbit?

General Definition of work: W=(line integral) F * ds , F=force vector, ds=infinitesimal displacement vector, *=dot product.

We know that in circular motion, the velocity vector is always perpendicular to the centripetal acceleration (I think we assume that centripetal acceleration is equated to gravitational acceleration), so 0 = F * v for all positions. so that means that 0 = F * ds/dt. If F * ds =0 for all positions, then W = 0. Does 0 = F * ds/dt imply F * ds = 0?

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Correct.
 
putongren said:
Does the gravity of Earth do any work on satellites orbiting the planet, assuming perfect circular orbit?
Perfect circular orbit means: potential energy doesn't change and kinetic energy doesn't change so there is no work to do.
 
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