Does Energy Decay Occur in Sealed Metal Boxes with Excited Resonant Modes?

AI Thread Summary
Exciting resonant modes in a sealed metal box can be achieved by using an antenna, such as a dipole, placed at the anti-node of the desired mode. The excitation can occur through incident electromagnetic radiation, which penetrates the metal via skin effect, assuming the metal thickness allows for minimal attenuation. Energy stored in the box will decay over time, primarily due to resistive losses from the non-perfect conductivity of the metal walls. This decay is exponential, similar to the process by which the modes were initially excited. Understanding these dynamics is crucial for effective energy management within the cavity.
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Hey there, I recently solved for the resonant modes in a 3d metal box.

Thats nice, but I was wondering about how to actually excite the modes (its a sealed metal box)
Supposing I actually excited these modes by shining incident em radiation such that a portion [of the incident wave] penetrates by skin effect (assuming the thickness of the metal allows for penetration without too much attenuation).

Will I subsequently have gradual decay of the energy stored in my box? I.e will my resonant mode 'leak' out by a similar process as they were originally excited with?

Thanks-Hopefully that was cogent.
 
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Are you asking how to excite a cavity in your simulations? Or in the real world?
If it is the latter the answer is that this can be done with a small antenna (a dipole of some sort) placed where the mode you want to excite has an anti-node.
The idea is usually (but not always) to make the antenna so small that losses due to the coupling can be neglected (although if you actually want to measure what is inside your box you have no choice but to "tap" some of its energy).
In the undercoupled case most of the losses will be due to the fact that the walls are made from a non-perfect conductor, i.e. just resistive losses.

And yes, the energy in the box will decay exponentially,
 
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