Does et^2 Satisfy the Growth Restriction for Laplace Transform?

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SUMMARY

The discussion centers on proving that the function e^(t^2) does not satisfy the growth restriction required for the Laplace transform, specifically the condition U(t) < M e^(kt). The participants analyze the inequality t^2 < ln(M e^(kt)), leading to the conclusion that as t approaches infinity, the left side becomes unbounded while the right side remains constant. Thus, the inequality t^2 - kt < ln(M) cannot hold for all t, confirming that e^(t^2) fails to meet the necessary criteria for the Laplace transform.

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KateyLou
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Homework Statement


The condition to be satisfied for a Laplace transform is U(t)<Mekt


Homework Equations


I am trying to proove that et2 does not satisfy this


The Attempt at a Solution


It was suggested that we try taking logarithms of both side:
t2<ln(Mekt)
t2<lnM+lnekt
t2<lnM+kt
t2-kt<ln M

I don't think this shows anything?!
 
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Sure it shows something. t^2-kt is unbounded as t->infinity. ln(M) is a constant. t^2-kt<ln(M) can't be true for all t.
 
YAY! Thank you!
 

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