Does Falling Speed Differ from speed?

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When an object falls, its vertical falling speed is independent of its horizontal speed, assuming no air resistance. In the presence of air resistance, both a falling bullet and a fired bullet will hit the ground simultaneously if dropped from the same height, but air resistance will affect their descent. The bullet's horizontal speed introduces a horizontal force that experiences friction opposing its motion, while gravitational force acts downward. Air resistance does slow down the bullet's descent slightly, but the effect is minimal for bullets due to their high velocity. Overall, the vertical motion remains unaffected by horizontal speed in terms of timing, though air resistance plays a role in overall descent speed.
aosome23
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Hello,

This is a quick question that I want to know,
When an object falls, does the vertical falling speed stay the same with any horizontal speed?

To be more clear about this question, this is an example:
There is a bullet.
1. The bullet falls from 10 meters above the ground without any change in rotation.
2. The bullet is fired from 10 meters above the ground, again without any change in rotation.I know that it will hit the ground at the same time if there is no air resistance but I don't know which one will hit the ground earlier where there is air resistance? Will the speed of the bullet matter? Does air actually make it fall slower?

Thank you.
 
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Yes air will make it fall slower, but in the case of a bullet, very little. Friction always acts directly opposite to the direction of motion.

For your question, you can break the forces up into their components. There is an initial force horizontally when the bullet is shot, so friction will oppose in the horizontal direction. There is also a gravitational force pointed downwards, where the friction is opposing upwards. When the bullet isn't shot, there will be no horizontal force, but that will not effect the vertical force.
 
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I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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