Looking at the Friedmann equation(adsbygoogle = window.adsbygoogle || []).push({});

[tex]H^2=\left[\frac{\dot{a}}{a}\right]^2=\frac{8\pi G\rho}{3}-\frac{kc^2}{a^2}[/tex]

and considering positive curvature, then for the limit where the second term dominates, we're left with

[tex]\left[\frac{\dot{a}}{a}\right]^2=-\frac{kc^2}{a^2}[/tex]

This implies a complex scale factor, does it not?

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# Does Friedmann equation allow for complex scale factor?

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