Does L'Hospital's rule apply to complex functions?

[quasar987]

I have to evaluate

\lim_{x\rightarrow \infty} \frac{x-1}{e^{ipx/\hbar}}

is this equal to

\lim_{x\rightarrow \infty} \frac{\hbar}{ip e^{ipx/\hbar}}

??

 

[LeonhardEuler]

L'Hospital's rule only applies when a limit approaches \frac{0}{0} or \frac{\infty}{\infty}. Niether is the case here because \lim_{x\rightarrow\infty}e^{ix} does not exist. The real and imaginary parts oscilate between -1 and 1 as x approaches infinity. Your limit is equal to:
\lim_{x\rightarrow \infty} \frac{x-1}{e^{ipx/\hbar}} =\lim_{x\rightarrow \infty} (x-1)\cos{\frac{ipx}{\hbar}}-i(x-1)\sin{\frac{ipx}{\hbar}
So the real and imaginary parts both oscillate between larger and larger positive and negative numbers as x gets larger, so the limit does not exist.

 

[quasar987]

Dang. I guess I was trying a little too hard to make this QM problem work

 

[nhrock3]

ok so the answer is infinity
we have some thing bounded in the denominator
and the numerator goes to infinity

 

[Count Iblis]

I suggest you choose different boundary conditions at infinity for your QM problem.