Does Light Frequency Change When Entering a Solid?

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SUMMARY

The discussion centers on the behavior of light waves when transitioning from air to a transparent solid. A light wave with a wavelength of 678 nm in air has a frequency of 4.42e16 Hz, calculated using the formula v = λf. The correct wavelength conversion reveals that 678 nm equals 6.78e-7 m, leading to a corrected frequency calculation. It is established that the frequency of light remains constant when entering different media, while the speed of light changes based on the medium's refractive index.

PREREQUISITES
  • Understanding of the wave equation v = λf
  • Knowledge of light properties, specifically wavelength and frequency
  • Familiarity with unit conversions, particularly nanometers to meters
  • Basic principles of optics, including light behavior in different media
NEXT STEPS
  • Study the concept of refractive index and its effect on light speed
  • Learn about the relationship between wavelength, frequency, and speed of light in various media
  • Explore the principles of Snell's Law and light refraction
  • Investigate the implications of light frequency constancy across different materials
USEFUL FOR

Students studying physics, particularly those focusing on optics, as well as educators and anyone interested in the properties of light and its behavior in different media.

Mohji
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Homework Statement



A light wave has a 678 nm wavelength in air. Its wavelength in a transparent solid is 493 nm.

a) What is the speed of light in this solid?
b) What is the light's frequency in the solid?

Homework Equations



v = λf

The Attempt at a Solution



a) I got the correct answer for this one. Let v1 and λ1 be speed of light and wavelength in air, v2 and λ2 in solid.

v1 = λ1f
f = v1 / λ1
f = (3.00e8 m/s) / (6.78e-9 m)
f = 4.42e16 Hz

v2 = λ2f
v2 = (4.93e-9 m) (4.42e16 Hz)
v2 = 2.18e8 m/s

This is the correct answer.

b) I was under the impression that the frequency of light does not change from one medium to another, meaning it would still be 4.42e16 Hz. This is the principle that I used to solve a). However, the online assignment keeps telling me that the answer is incorrect.

Am I making a mistake here? Any help would be greatly appreciated.
 
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Mohji said:
v1 = λ1f
f = v1 / λ1
f = (3.00e8 m/s) / (6.78e-9 m)
f = 4.42e16 Hz

You made a mistake here, the wavelength 678 nm is 6.78 e-7 m, so your frequency is wrong.

And you are right, the frequency does not change when the light wave enters into an other medium.

ehild
 
ehild said:
You made a mistake here, the wavelength 678 nm is 6.78 e-7 m, so your frequency is wrong.

And you are right, the frequency does not change when the light wave enters into an other medium.

ehild

D'oh! Always overlook the possibility of something small like a conversion error. Thanks a lot for the quick reply.
 

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