Does Monotone Convergence imply Convergence Subsequence?

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SUMMARY

The discussion centers on the implications of monotone convergence in relation to subsequences. It establishes that if a sequence (a_n) converges to a limit L, then any subsequence (a_{n_r}) also converges to L. Conversely, if (a_n) is an increasing sequence and diverges, all its subsequences must also diverge. The conclusion drawn is that for an increasing sequence to be convergent, it must be bounded, thereby ensuring convergence.

PREREQUISITES
  • Understanding of sequences and limits in real analysis
  • Familiarity with the concepts of monotonicity and boundedness
  • Knowledge of subsequences and their convergence properties
  • Basic principles of divergence in sequences
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  • Study the properties of monotone sequences and their convergence criteria
  • Learn about the Bolzano-Weierstrass theorem regarding bounded sequences
  • Explore examples of oscillating sequences and their divergence
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Mathematics students, particularly those studying real analysis, educators teaching convergence concepts, and anyone interested in the properties of sequences and subsequences.

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i) if (a_n) tends to L as n tends to infinity, then a_{n_r} tends to L as r tend to infinity

ii)if (a_n) tends to infinity as n tends to infinity, then a_{n_r} tends to infinity as r tend to infinity

using this result prove that

if (a_n) is an increasing sequence, prove that the converse of i) is true
Suppose (a_n) is divergent, then by ii), all the subsequences must be divergent, so, cant.

therefore (a_n) must be convergent, means (a_n) tends to M for some M,

apply i), then means M=L

but how come i didn't use the fact (a_n) is monotone, must be something wrong somewhere, help T_T
 
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"Tends to infinity" is not the only way a sequence can diverge. Oscillating sequences are also divergent.
 
aaaaaaaaaaaarghh, yes yes, thank you ^^

hmm, now i have to prove that <br /> (a_n)<br /> is convergent,

i suspect i should prove that <br /> (a_n)<br /> is bounded then, i know <br /> (a_n)<br /> is monotone then, <br /> (a_n)<br /> must be converging right? then continue like i was doing above right?
 
Last edited:
That sounds correct.
 
thank you very much
 

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