Every subsequence converges to L implies a_n -> L

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Homework Help Overview

The problem involves a bounded sequence ##\{a_n\}## where it is given that every convergent subsequence has a limit ##L##. The task is to prove that the sequence itself converges to ##L##.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Some participants explore the relationship between the sequence and its subsequences, questioning whether the original sequence can be considered a subsequence. Others suggest using the concepts of ##\liminf## and ##\limsup## to analyze the limits of the sequence.

Discussion Status

There is ongoing exploration of the implications of the given conditions, with hints provided regarding the use of ##\liminf## and ##\limsup##. Some participants express confidence in their reasoning, while others are still clarifying their understanding of the problem.

Contextual Notes

Participants note the importance of the distinction between convergent subsequences and the original sequence, as well as the implications of the limits of subsequences on the overall sequence.

Mr Davis 97
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Homework Statement


Let ##\{a_n\}## be a bounded sequence such that every convergent subsequence has limit ##L##. Prove that ##\lim_{n\to\infty}a_n = L##.

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The Attempt at a Solution


I'm not really understanding this problem. Isn't ##\{a_n\}## a subsequence of itself? So isn't it immediately the case that ##\lim_{n\to\infty}a_n = L## by the hypothesis?

EDIT: Nevermind. I notice now that it says every convergent subsequence.
 
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Hint: This is easy considering ##\liminf_{n \to \infty}a_n## and ## \limsup_{n \to \infty} a_n##
 
Math_QED said:
Hint: This is easy considering ##\liminf_{n \to \infty}a_n## and ## \limsup_{n \to \infty} a_n##
Could we just say that since the set of subsequential limits is just ##\{L\}##, we have that ##\limsup a_n = \sup \{L\} = L = \inf \{L\} = \liminf a_n##. So ##\lim_{n\to\infty} a_n = L##?
 
Mr Davis 97 said:
Could we just say that since the set of subsequential limits is just ##\{L\}##, we have that ##\limsup a_n = \sup \{L\} = L = \inf \{L\} = \liminf a_n##. So ##\lim_{n\to\infty} a_n = L##?

Exactly. Well done!
 

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