All degrees are measured from the positive x-axis. FG = Force of gravity FN = Normal force FT = Force of tension Problem: A skier is being pulled up a 15° incline by a rope. I'm solving for FT. The only forces acting on the skier are FG, FN, and FT. Attempt at a solution: Initially, my free-body diagram shows the FG at 270°, FN at 105°, and FT at 15°. Let's say I redraw my free-body diagram such that FG points at 255° FN at 90°, and FT at 0° (or 360°). FyG =-mgcosθ. What I want to know is, does my FyN = +mgcosθ, or just +mg?