Does PNP transistor share the same formulas as an NPN transistor?

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Discussion Overview

The discussion centers around whether the formulas used for NPN transistors also apply to PNP transistors, exploring the similarities and differences in their operation and equations.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • Some participants present formulas for transistor operation, including Beta = Ic/Ib, Ie = Ib (1 + beta), and Ie = Ib + Ic.
  • One participant asserts that the formulas apply to both PNP and NPN transistors, noting that the polarity is reversed.
  • Another participant highlights that the difference lies in the sign of Vbe for NPN and Veb for PNP.
  • A participant suggests that if no good reason can be found to disallow the equations, they should be applicable to both types of transistors.
  • One participant shares a diagram intended to clarify the discussion.
  • Another expresses gratitude for the validation of their understanding.

Areas of Agreement / Disagreement

Participants generally agree that the formulas can apply to both types of transistors, but there is a discussion about the implications of polarity differences. No consensus is reached on the broader implications of these equations.

Contextual Notes

The discussion does not resolve potential limitations or assumptions regarding the application of the formulas to different transistor types.

Femme_physics
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The formulas in question are:

Beta = Ic/Ib
Ie = Ib ( 1 + beta )
Ie = Ib + Ic
 
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Yes, of course. Though the polarity is reversed. The terminals are named such that those equations are obeyed for both pnp and npn transistors.
 
Ahh...got it, so really the only difference is that +Vbe in NPN becomes +Veb in PNP

Thanks
 
You could ask yourself why the equations shouldn't apply. If you can't come up with a good reason then they would apply.
 
This diagram show everything
96_1250754356.png
 
Thanks for the validation :)
 

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