Does Reducing a Satellite's Speed Guarantee Its Descent to Earth?

AI Thread Summary
Reducing a satellite's speed does not guarantee its immediate descent to Earth; instead, it will enter an elliptical orbit. The point of maximum radius, or apogee, occurs where the speed was reduced, while the point of minimum radius, or perigee, determines if it will eventually collide with Earth. If the perigee falls below the Earth's surface, the satellite will re-enter the atmosphere and crash. To calculate the impact point on Earth, one must consider the new orbital parameters after speed reduction. Understanding these dynamics is crucial for predicting satellite behavior post-speed alteration.
goh
Messages
1
Reaction score
0
Suppose we have a satellite orbiting in circular motion around the Earth (steady velocity) in a radius R.Everything is ok now.
If suddenly we reduce the speed of the satellite is it bound to fall to the Earth ? Or it can continue moving in circular orbit with smaller R ? If i want it to fall , how can i calculate where on Earth does it fall ? And what should be the reduced speed so it will fall there ?
Ok I am not expecting from you to tell me all the exact equations to solve this but some general eplain would be useful. Thanks
 
Physics news on Phys.org
goh said:
If suddenly we reduce the speed of the satellite is it bound to fall to the Earth ? Or it can continue moving in circular orbit with smaller R ?

It will start to move in an elliptical orbit whose apogee (point of maximum R) is at the point where the speed was suddenly reduced. If the perigee (point of minimum R) of the new orbit lies below the Earth's surface (or better for practical purposes, within the Earth's atmosphere), then the satellite will hit the earth.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top