Does RMS(f1) +RMS(F2) = RMS(F1+F2)?

  • Thread starter lennybogzy
  • Start date
  • #1
94
0
If I hava non periodic waveform and I divide it into 3 cycles is taking the RMS of each cycle and averaging the same thing as taking the RMS of all 3 cycles at once?
 

Answers and Replies

  • #2
es1
324
0
In general this is not true.

Let f1(t)=1 and and f2(t)=-1

rms(f1)=1
rms(f2)=1
rms(f1+f2)=0
 
  • #3
es1
324
0
Just out of curiosity, if the signal is non-periodic, how did you determine how big a cycle is?
 
  • #4
5,527
195
If it is non periodic, you need to find the average rates to do RMS calculation. That is if you have a random pulses, you need to use a frequency counter and find the pulse rate, then you can use the amplitude to get the RMS amplitude.

I did a lot of pulse counting work, they are random, just like current, it is not steady in microscopic level, we say it is 1A only because in average there are so many electrons part a point per second and we use that as the average current....Yes, current is a stream of electrons passing in a random rate.
 

Related Threads on Does RMS(f1) +RMS(F2) = RMS(F1+F2)?

Replies
9
Views
5K
  • Last Post
Replies
6
Views
2K
  • Last Post
2
Replies
36
Views
8K
  • Last Post
Replies
1
Views
2K
Replies
5
Views
3K
  • Last Post
Replies
3
Views
3K
  • Last Post
Replies
1
Views
8K
  • Last Post
Replies
5
Views
20K
  • Last Post
Replies
1
Views
624
  • Last Post
Replies
10
Views
10K
Top