I Does the expansion of the Universe affect orbiting bodies?

Click For Summary
The expansion of the universe does not affect the orbits of gravitationally bound systems, such as galaxies and local groups. Objects like the Magellanic Clouds, which are bound to the Milky Way, will not experience changes in their orbits due to cosmic expansion. While distant objects may recede from each other due to the expansion of space, this does not alter the dynamics of bound systems. The concept of being "gravitationally bound" means that these systems cannot escape each other's gravitational influence without additional energy. Therefore, the orbits of the Magellanic Clouds remain stable regardless of the universe's expansion.
  • #31
Buzz Bloom said:
For a two body example, one can use the rule that if a body has a distance from and a velocity relative to another body, and this velocity is less than the escape velocity, then the two are bound.

Yes, this is the general rule.

Buzz Bloom said:
if one body has less mass than the other body the rule might say that the lighter body might be bound to the heavier body, but not necessarily vice versa. Or I might be mistaken about this.

Yes, you're mistaken. "Bound" is a state of the system of bodies, not of one body or the other. The escape velocity criterion is the escape velocity from the system, based on the total mass of the system. So, for example, the escape velocity from the Milky Way galaxy at the location of the solar system is due to the mass of the entire galaxy--or more precisely that portion of the galaxy that is closer to the center than the solar system is.

In other words, what "escape" means, and therefore what "bound" means, depends on what system you are looking at. The escape velocity from the solar system at the Earth's location is the velocity required to escape the solar system--but escaping the solar system is not the same as escaping the Milky Way galaxy, which in turn is not the same as escaping the Local Group, which in turn is not the same as escaping the entire galaxy cluster of which the Local Group is a part.

Buzz Bloom said:
Regarding (2), this might mean either

It means (a) as far as expansion itself is concerned. It means (b) as far as dark energy specifically is concerned. See further comments below.

Buzz Bloom said:
I gather the McVitte metric should be able to make a clear distinction between (2a) or (2b).

The McVittie metric itself is highly unrealistic for analyzing bound systems for the same reason FRW metrics in general are: it assumes that there is a uniform density of matter everywhere, except for (in the McVittie case) a single "mass" at the spatial origin. But that is not true of the actual universe. In the actual universe, any bound system, whether it's a planet, star, solar system, galaxy, or galaxy cluster, is surrounded by empty space. So any metric that assumes a uniform density of matter where there is actually empty space will lead to an incorrect model.

In an FRW-type spacetime (where "FRW-type" is meant to include the McVittie metric), the uniform density of matter everywhere, in the form of a perfect fluid, and the fact that the matter is everywhere expanding, does exert what amounts to a "pull" on any object that is embedded in the fluid. So any object embedded in the fluid, unless it is moving with exactly the "comoving" fluid velocity at its location, will feel a force that tends to make it move with the comoving fluid velocity.

However, this force is not exerted by "space"; it's exerted by the perfect fluid matter that is of uniform density everywhere. The presence of that uniform density everywhere is what produces the force; so in the real universe, where there is not uniform perfect fluid matter everywhere but isolated bound systems surrounded by empty space, this "force" simply does not exist. In other words, the FRW-type model that assumes a uniform density of perfect fluid everywhere is simply an incorrect model for analyzing bound systems in the actual universe. And that is why the expansion of the universe, by itself, does not affect the motion of objects in bound systems at all (your option 2 (a) above).

In a universe with dark energy, as we believe our universe to be, the dark energy is the sole exception to the above, because, as far as we can tell, dark energy is present in a uniform density everywhere. So what we have been calling "empty space" up to now, within and surrounding all bound systems, is not actually completely empty; it has dark energy in it. And because it is present in a uniform density everywhere, dark energy does exert a force everywhere that tends to push things apart. So dark energy does have a (tiny) effect on, for example, the motion of objects in the solar system, or in the Milky Way galaxy, etc. (your option 2 (b) above). But it's far too tiny for us to be able to measure it, so for practical purposes we can ignore it.
 
Astronomy news on Phys.org
  • #32
Ibix said:
The fundamental fact is that, at small scales, the universe is not FLRW and never was

The "never was" part isn't necessarily true. If you go back early enough, the universe was filled with matter (and radiation) everywhere, with a density that was close to uniform everywhere. (But not exactly uniform--the small inhomogeneities that existed then ended up leading to the much larger inhomogeneities we have now.) So an FRW model actually was a reasonable model even on small scales in the early universe. It got less and less reasonable on small scales (and what scale counted as "small" got larger and larger) as the universe developed more and more structure.
 
  • #33
PeterDonis said:
So an FRW model actually was a reasonable model even on small scales in the early universe. It got less and less reasonable on small scales (and what scale counted as "small" got larger and larger) as the universe developed more and more structure.
So both the degree and scale of inhomogeneity grow with time. Is it correct to say something like "there is always a scale (which shrinks as you go back in time) below which the universe is not FLRW to some precision (which gets tighter as you go back in time"?
 
  • #34
PeterDonis said:
In a universe with dark energy, as we believe our universe to be, the dark energy is the sole exception to the above, because, as far as we can tell, dark energy is present in a uniform density everywhere. So what we have been calling "empty space" up to now, within and surrounding all bound systems, is not actually completely empty; it has dark energy in it. And because it is present in a uniform density everywhere, dark energy does exert a force everywhere that tends to push things apart. So dark energy does have a (tiny) effect on, for example, the motion of objects in the solar system, or in the Milky Way galaxy, etc. (your option 2 (b) above). But it's far too tiny for us to be able to measure it, so for practical purposes we can ignore it.

How would you describe the solution when it comes to the local group of galaxies and, in particular, the collision of the Milky Way and Andromeda? The distances here are significant if we plug in the current universe expansion rate. But, is this valid? That expansion rate is based on the overall universal balance of mass/vacuum. How would the universe expansion rate get into the equations for the dynamics of the local group?

Instead, should we model the local group using the specific mass/vacuum density we find in this region? This would then include a small element due to the dark energy, but would still be largely negligible.

Can these two models be tested against the observed separation velocity?
 
  • #35
Ibix said:
Is it correct to say something like "there is always a scale (which shrinks as you go back in time) below which the universe is not FLRW to some precision (which gets tighter as you go back in time"?

Probably, at least back to the end of inflation, since our best current model says that it was tiny inhomogeneities at the end of inflation (due to quantum fluctuations in the inflaton field) that eventually grew into the structures we see today.
 
  • Like
Likes Ibix
  • #36
PeroK said:
How would you describe the solution when it comes to the local group of galaxies and, in particular, the collision of the Milky Way and Andromeda?

The local group is a bound system surrounded by empty space (unless we include dark energy, but on this scale dark energy effects are still too small to matter). So it would be modeled as a bound system surrounded by empty space.

PeroK said:
The distances here are significant if we plug in the current universe expansion rate.

You can multiply any distance you like by the Hubble constant and get a speed. That in itself doesn't mean the speed has any physical significance.

The correct criterion, as I've already said, is what matter is actually present in the region of spacetime you are talking about. The Local Group of galaxies, as above, is a bound system surrounded by empty space. There is no "expansion velocity" in such a system. The fact that the FRW model for the universe as a whole has a Hubble constant that I can multiply by, say, a million light-years to get a speed, is irrelevant, since the FRW model is simply not a correct model for a bound system surrounded by empty space.

PeroK said:
That expansion rate is based on the overall universal balance of mass/vacuum.

More precisely, it's based on assuming that the universe is filled with a uniform density perfect fluid, with the density given by the average density for the universe as a whole.

PeroK said:
How would the universe expansion rate get into the equations for the dynamics of the local group?

It wouldn't, since the local group is not composed of a uniform density perfect fluid.

PeroK said:
should we model the local group using the specific mass/vacuum density we find in this region?

Using the specific mass/vacuum distribution we find in the region, on whatever length scales are relevant for the question we are trying to answer.

PeroK said:
Can these two models be tested against the observed separation velocity?

The FRW model is obviously false for the Milky Way and the Andromeda galaxy, since they are moving towards each other whereas the FRW model says they should be moving apart.
 
  • Like
Likes PeroK
  • #37
PeterDonis said:
The FRW model is obviously false for the Milky Way and the Andromeda galaxy, since they are moving towards each other whereas the FRW model says they should be moving apart.

What's being proposed, as I understand it, is a hybrid model where we simply layer a universal expansion rate on top of the local dynamics. This would reduce very significantly but not eliminate the attraction between the local galaxies. This seems to be a widespread misapprehension.
 
  • Like
Likes Ibix
  • #38
PeroK said:
What's being proposed, as I understand it, is a hybrid model where we simply layer a universal expansion rate on top of the local dynamics. This would reduce very significantly but not eliminate the attraction between the local galaxies. This seems to be a widespread misapprehension.
I agree with your interpretation of what's being proposed, and it's not an unreasonable reading of "space is expanding". Unfortunately, it's wrong. It's certainly possible that dark energy (or a similar phenomenon) is pushing outwards slightly on the solar system and/or Andromeda and the Milky Way, but that would be below our detection level. And dark energy (etc) isn't responsible for the expansion of the universe - it's a tiny tweak to the expansion profile. So while it might be correct to say that dark energy has an effect on the motions of planets/stars/galaxies, that's not the same as saying expansion has an effect on their motions.
 
  • Like
Likes PeroK
  • #39
PeroK said:
What's being proposed, as I understand it, is a hybrid model where we simply layer a universal expansion rate on top of the local dynamics.

Proposed by whom? What are you referring to?
 
  • #40
PeterDonis said:
Proposed by whom? What are you referring to?
alantheastronomer said:
To see just how significant the effect is, the distance to Andromeda is two and a half million light years. The current value of the expansion rate is 70km/sec per megaparsec, so the expansion contributes 55km/sec to Andromeda's recession from the Milky Way. But these two galaxies are supposed to collide in five billion years, approaching each other with a velocity of 110km/sec. What this means is that, were the universe not expanding, the two galaxies would be approaching each other at a speed of 165km/sec and collide in three billion years instead. I have no idea whether or not this expansion has been taken into account in the calculation of the collision's timescale.
 
  • #41
PeterDonis said:
Proposed by whom?

Ah, ok. I think I've already explained in quite a bit of detail what is wrong with this proposal.
 
  • #42
Ibix said:
it's not an unreasonable reading of "space is expanding"

Not unreasonable if all you have looked at is pop science sources, perhaps. But that just underscores the point that you should not be trying to learn science from pop science sources.
 
  • #43
ERRORS HAVE BEEN FIXED.

Ibix said:
If the universe were everywhere filled with a perfect fluid (this is made up of genuinely continuous matter, not of atoms or anything - don't ask too many questions) that was everywhere of uniform density and pressure, then that universe would be accurately described by an FLRW spacetime.
...
The real universe is rather like this at very large scales.
...
I think your attempt to understand "bound systems" in an expanding universe is probably the wrong way to look at this.

PeterDonis said:
Yes, you're mistaken. "Bound" is a state of the system of bodies, not of one body or the other. The escape velocity criterion is the escape velocity from the system, based on the total mass of the system.
...
In other words, what "escape" means, and therefore what "bound" means, depends on what system you are looking at.
...
The McVittie metric itself is highly unrealistic for analyzing bound systems for the same reason FLRW metrics in general are: it assumes that there is a uniform density of matter everywhere, except for (in the McVittie case) a single "mass" at the spatial origin. But that is not true of the actual universe.
Hi Ibiz and Peter:

I do appreciate your posts, but I still feel the need to ask a few followup questions.

Am I wrong to assume that the math of various models are able to make reasonable predictions about the behavior of the models, even if the models have flaws with respect to the real universe? I certainty understand that the McVitty model, combining Schwartzschild and FLRW math, is not a realistic model of our real universe. Suppose I take the simplest case in which there is a single black hole mass, and a FLRW model as follows:
MODEL 1:
M = the mass of our sun.​
ΩR is very small, say the value in our actual current universe, say​
ΩR = ε,​
ΩR is very small, say the value in our actual current universe, say​
ΩM = 0,​
Ωk = 0,​
and
ΩΛ = 1-ε.​
Assume a spherical ball of spherically symmetric mass equal to mass m of Earth.
Assume mass m is in a circular orbit around mass M as a distance R of exactly
R = 149.60×106 km.​
As I understand properly what I read in Wikipedia, this circular orbit would have an average orbital velocity very close to
V = 29.78 km/s.​
The reason I have a non-zero ΩR is so that there can be a CBR which is useful in determining whether a particle is stationary with respect to co-moving coordinates, or if moving, the velocity can be measured based on differences in CBR differences in different directions
MODEL 2:
(This model previously had several serious errors which are now fixed.)
The model is the same as MODEL 1 except for the following differences.
Ωk = η<0, 0<ε<|η|<<1.​
ΩM = 1-ε-η>1​
assumed to be uniformly distributed dark matter with no forces acting between particles,
and
ΩΛ = 0.​
For this model the it is possible for the universe to (at least for a while) stay at a constant scale factor, which means no expansion would be taking place.

What I would like to find out, either from someone else, or if necessary from my own efforts to work with the McVitte metric, is whether or not the MODEL 2 orbit would be identical with the MODEL 1 orbit. My current uniformed guess (which certainly may be wrong) is that MODEL 2 would have a very small but non-zero difference from MODEL 1. In particular the MODEL 2 orbital radius would be slightly smaller, and the orbital velocity slightly faster.

I also want to explore MODEL 1 in which the distance D between the M and m masses satisfies
D3 = GM/H2.​
BTW, a very rough calculation is that this D value is about 3000 light years. I am wondering is the McVitty math can show that at the exact distance D the MODEL 2 orbital velocity would be zero.

Regards,
Buzz
 
Last edited:
  • #44
Buzz Bloom said:
Am I wrong to assume that the math of various models are able to make reasonable predictions about the behavior of the models

Of course not. You can always get mathematical predictions from the models. But if a model is already known to not be a good model for the actual universe, I don't see the point of spending a lot of time trying to calculate predictions from it. You'll just be calculating a lot of things that don't match up to our actual universe.
 
  • #45
Buzz Bloom said:
For this model the universe it is possible for the universe to (at least for a while) stay at a constant scale factor

I don't understand; your MODEL 2 appears to be a matter-dominated universe with no dark energy. It is impossible for such a universe to stay at a constant scale factor "for a while". At most, if it is closed, it will be at a constant scale factor for an instant, at maximum expansion.
 
  • #46
Buzz Bloom said:
MODEL 1

This appears to be a dark energy dominated universe with no matter and a smidgen of radiation. (Btw, the value of ##\epsilon## that would approximate our current CMBR as compared to the rest of the matter and dark energy in our actual universe is about ##10^{-4}## IIRC.) In such a universe, the presence of dark energy does indeed have a tiny effect on the orbital parameters of an object like the Earth orbiting the Sun. The simplest way to view the effect is that it makes the orbital velocity required to maintain orbit at a given altitude very slightly smaller than it would be in the absence of dark energy. The presence of the radiation has an even smaller effect in the opposite direction, i.e., requiring a very, very slightly larger orbital velocity at a given altitude.
 
  • #47
Hi @PeterDonis :

Thank you for your responses. I have realized that I made (at least) two errors in my post #43. I am going to (try to) fix them before I respond to your recent posts. I apologize for my carelessness.

Regards,
Buzz
 
  • #48
PeterDonis said:
Of course not. You can always get mathematical predictions from the models. But if a model is already known to not be a good model for the actual universe, I don't see the point of spending a lot of time trying to calculate predictions from it.
I interpret the above as being a confident statement that a conclusion reached by these unrealistic models, cannot possibly be useful for a realistic model. I suggest a hypothetical counter view. In particular, suppose hypothetically the exploration of a non-relaistic model like my MODEL 1 based on the McVitte metric demonstrates that for D satisfying
D3 = GM/H2
that Earth mass m is metastable (stable unless a perturbation destroys the stability) at zero velocity relative the mass M. Would not that then suggest that something (perhaps an effect of expansion) is apposing the gravitation acceleration on m due to M? Would this then also suggest that there might be a corresponding effect in a more realistic model?

Sorry, Peter. I have to stop posting for a while. My wife needs to use this computer now for several hours.

Regards,
Buzz
 
  • #49
Buzz Bloom said:
I interpret the above as being a confident statement that a conclusion reached by these unrealistic models, cannot possibly be useful for a realistic model.

Wrong conclusions are not useful, yes.

Buzz Bloom said:
Would not that then suggest that something (perhaps an effect of expansion) is apposing the gravitation acceleration on m due to M?

I've already said that, since your MODEL 1 is dark energy dominated, it does predict a tiny force tending to push things apart in the solar system. This is an obvious prediction of any dark energy dominated model. It is also irrelevant in practice to the dynamics of the solar system, for reasons already given (the effect is much too small in practice to be detectable).

So your MODEL 1 is not telling anyone anything they don't already know or making any practically useful prediction. But the reason has nothing whatever to do with the model being "unrealistic"; as I've already said, in the case of dark energy, we do think its density is uniform everywhere, so your MODEL 1 is perfectly realistic in that respect. It's just that the density of dark energy is so tiny that its effects are unmeasurable on solar system scales.

The model that I have been saying is "unrealistic" is a model like the McVittie metric for the matter dominated case, where the model assumes that there is a uniform density of ordinary matter everywhere in the universe, and tries to make claims about the dynamics of the solar system on that basis. I do not think the predicted "expansion" effects in such models exist at all on the scale of the solar system, precisely because we already know that there isn't a uniform density of ordinary matter on such scales; there are isolated stars and planets surrounded by empty space. And we already know how to model that using GR, and such models do not have any "expansion" effects.
 
  • #50
PeterDonis said:
I've already said that, since your MODEL 1 is dark energy dominated, it does predict a tiny force tending to push things apart in the solar system. This is an obvious prediction of any dark energy dominated model. It is also irrelevant in practice to the dynamics of the solar system, for reasons already given (the effect is much too small in practice to be detectable).
Hi Peter:

I interpret the above as saying that you agree that in the McVittie Model 1 there is a distance Dlim such that
(Eq 1) Dlim3 approx = GM/H2
at which the orbital velocity of the Earth object relative to the Sun object is zero. If this is correct this means that the definition of "boundeness" based on the escape velocity V defined as
(Eq 2) V2 = 2GM/D​
for any distance D is incomplete. A more complete test would include that if a particle is at a distance greater than the Dlim of (Eq 1) is is not bound to the central mass M, no matter what it's velocity is. Also, for any separation distance
D < Dlim,​
the escape velocity V (Eq 2) is too large. It needs to be reduced by an amount which can be calulated based on what you call the effect of ΩΛ.

Regards,
Buzz
 
Last edited:
  • #51
PeterDonis said:
I don't understand; your MODEL 2 appears to be a matter-dominated universe with no dark energy. It is impossible for such a universe to stay at a constant scale factor "for a while". At most, if it is closed, it will be at a constant scale factor for an instant, at maximum expansion.
Hi Peter:

You are correct, and I am wrong, and I apologize for my mistake. I recall working on calculating the range of Omega values that would allow for
(1) da/dt=0​
and
(2) d2a/dt2 = 0.​
If I remember correctly I did this about two years ago, and I had forgotten the need for dark energy. Aside from a diminishing of math skills, my memory is also not as good as when I was younger.

However, I believe this model is sufficient for my purposes with a value of a satisfying (1). I want to calculate what the difference is between the Model 1 and Model 2 orbits.

Regards,
Buzz
 
  • #52
Buzz Bloom said:
I interpret the above as saying that you agree that in the McVittie Model 1 there is a distance Dlim such that
(Eq 1) Dlim3 approx = GM/H2at which the orbital velocity of the Earth object relative to the Sun object is zero.

Meaning, in the Schwarzschild-de Sitter metric, since that is what "the McVittie Model 1" is--zero matter, zero radiation, only a cosmological constant. Yes, the statement is true, although I would phrase it somewhat differently, as I did in some thread or other recently (we have several threads now on the same general topic), that there will be some distance from the central mass at which an object can "hover" at a constant altitude with zero proper acceleration, i.e., by simply floating freely in space.

Buzz Bloom said:
if a particle is at a distance greater than the Dlim of (Eq 1) is is not bound to the central mass M, no matter what it's velocity is

No, this is not correct. The fact that the object can "float" at a constant altitude does not mean it can escape. You would still have to add energy to it for it to escape, where "escape" means "move away from the central mass indefinitely, without ever stopping or falling back".

But there is a more important issue that you are ignoring: in our actual universe, there are multiple isolated gravitating systems in a hierarchical structure, so the idea of "escape" has to be put in context. What does it mean to "escape" from the solar system? If I am halfway between the Sun and Alpha Centauri (supposing for a moment that their masses are equal), have I "escaped"? And even if I am well away from all stars in the immediate neighborhood, I'm still bound inside the Milky Way Galaxy. And even if I "escape" from the galaxy, I'm still bound inside the Local Group. And even if I "escape" from that, I'm still bound inside a larger galaxy cluster.

You are ignoring all of this hierarchical structure, and that's not really valid.
 
  • #53
Buzz Bloom said:
for any separation distance
D < Dlim,the escape velocity V (Eq 2) is too large.

I gave a formula for the case where the effects of dark energy are included in some post or other that's been linked to. This discussion is too spread out between multiple threads for me to find it right now.
 
  • #54
Buzz Bloom said:
I want to calculate what the difference is between the Model 1 and Model 2 orbits.

First you have to decide how you are going to find "the same" orbit in each model, in order to compare them. How will you do that?
 
  • #55
PeterDonis said:
First you have to decide how you are going to find "the same" orbit in each model, in order to compare them. How will you do that?
Hi Peter:

My thought about this is that the Sun mass M and Earth mass m are the same in the two MODELs. If I calculate the circular orbit velocity for each of the two MODELs, assuming the same distance D between the Earth and Sun, I expect the two orbital velocities to be slightly but non-zero different.

However, I still need to learn how to calculate a circular orbit given the metric. Any suggestions of what I should read would be appreciated.

Regards,
Buzz
 
  • #56
Buzz Bloom said:
My thought about this is that the Sun mass M and Earth mass m are the same in the two MODELs. If I calculate the circular orbit velocity for each of the two MODELs, assuming the same distance D between the Earth and Sun, I expect the two orbital velocities to be slightly but non-zero different.

Ok, so to be sure I understand, the models are:

MODEL 1: Sun mass M, nothing but dark energy everywhere else, Earth in circular orbit at proper distance D from the center of the Sun.

MODEL 2: Sun mass M, nothing but ordinary matter (i.e., uniform energy density, zero pressure) everywhere else, Earth in circular orbit at proper distance D from the center of the Sun.

And just for comparison:

MODEL 3: Sun mass M, vacuum everywhere else, Earth in circular orbit at proper distance D from the center of the Sun.

Is the above correct?
 
  • #57
PeterDonis said:
Is the above correct?

Note, btw, that I carefully said "proper distance D" instead of "radial coordinate D", since they're not the same.
 
  • #58
PeterDonis said:
MODEL 3: Sun mass M, vacuum everywhere else, Earth in circular orbit at proper distance D from the center of the Sun.

I should also note, btw, that as far as the Earth's orbit about the Sun is concerned, MODEL 3 is exactly equivalent in all its predictions to:

MODEL 3A: Sun mass M, vacuum out to some proper distance A that is larger than the proper distance D of Earth from Sun in its circular orbit, and any spherically symmetric distribution of stress-energy outside proper distance A. (And if we substitute "solar system", and distance A is large enough to be larger than the distance of any object in the solar system from the Sun, the same applies, and similarly for any bound system, up to and including galaxy clusters.)
 
  • #59
PeterDonis said:
Ok, so to be sure I understand, the models are:
...
Is the above correct?
...
Note, btw, that I carefully said "proper distance D" instead of "radial coordinate D", since they're not the same.

Hi Peter:

Those three models, and perhaps a few more I haven't yet decided on yet, are what I currently have in mind to calculate. So I agree that the models you listed "are correct".

I did notice your use of "proper distance", and I agree that may be correct distance I should use. Thank you for mentioning that. However, I am not sure the proper distance from the center of the sun is able to be calculated. It may be necessary to use instead the proper distance from the Sun's Schwartzschild radius (usually denoted as rs) to the Earth center, or maybe to the Earth's rs. Or maybe using the coordinate r distance would be OK. After I learn about calculating a circular orbit's velocity, I expect I will be able to chose a reasonable definition for "distance".

Regards,
Buzz
 
  • #60
Buzz Bloom said:
However, I am not sure the proper distance from the center of the sun is able to be calculated.

Sure it can. It just can't be expressed in a closed-form formula, unless you make the highly unrealistic assumption that the Sun's density is constant everywhere inside it. But reasonable approximations can be made, especially for the weak field case, which should be sufficient for this discussion.

Buzz Bloom said:
It may be necessary to use instead the proper distance from the Sun's Schwartzschild radius

The Sun isn't a black hole, so this radius is irrelevant since it doesn't pick out any location of physical significance (same for the Earth).
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
553
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 46 ·
2
Replies
46
Views
990