Does the Series \(\sum_{k=1}^{\infty}\frac{2+(-1)^k}{5^k}\) Converge?

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Homework Help Overview

The discussion revolves around the convergence of the series \(\sum_{k=1}^{\infty}\frac{2+(-1)^k}{5^k}\), with participants exploring various convergence tests and approaches to analyze the series.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine convergence using the comparison test and d'Alembert's test but finds them unhelpful. Suggestions include breaking the series into two parts and considering alternative tests such as the root test. Another participant raises a new question about a different series involving trigonometric functions.

Discussion Status

The discussion is active, with participants offering suggestions and exploring different tests for convergence. There is a transition to a new question regarding a different series, indicating ongoing engagement and inquiry.

Contextual Notes

Participants are navigating the constraints of their current knowledge in calculus, particularly regarding convergence tests and handling trigonometric series.

fishingspree2
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[tex]\sum_{k=1}^{\infty}\frac{2+\left(-1 \right)^{k}}{5^{k}}[/tex]

Hello, I am trying to determine if this series converges or diverges. I have tried comparison test and d'Alembert's test but I was not successful

Can anyone suggest me a test learned in Calculus 2 that will work?

Thank you
 
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Break it into a sum of two series?
 
Since you're asking if there exists another test you could also use.

[tex] \lim_{n \to \infty}\sqrt[n]{|a_n|}<1[/tex]

It converges absolutely if the limit is smaller than 1.
 
Thank you, I have figured it out. I have another question if you don't mind

[tex]\sum_{k=1}^{\infty}\frac{\left|\cos k \right|}{k^{3}}[/tex]

It looks like a riemann series but I don't really know how to deal with trigonometric functions in series yet. What to do? Can anyone explain me?

Thank you
 
What values can |cos k| take? Perhaps consider a p-series
 

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