Does the Tennis Ball Clear the Net?

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SUMMARY

The physics problem involves determining if a tennis ball, hit at a height of 2 meters with an initial speed of 20 m/s at an angle of 5 degrees, clears a net that is 1 meter high and located 7 meters away. The correct approach requires breaking down the motion into horizontal and vertical components. The horizontal velocity is calculated using the cosine of the angle, while the vertical motion is analyzed using the equation d = vit + 1/2at², where the only acceleration considered is due to gravity (9.81 m/s²). Following this method confirms whether the ball clears the net or not.

PREREQUISITES
  • Understanding of projectile motion in physics
  • Knowledge of kinematic equations, specifically d = vit + 1/2at²
  • Ability to resolve vectors into horizontal and vertical components
  • Familiarity with basic trigonometry, particularly sine and cosine functions
NEXT STEPS
  • Calculate horizontal and vertical components of velocity using trigonometric functions
  • Learn how to apply kinematic equations to projectile motion problems
  • Study the effects of gravity on projectile trajectories
  • Explore more complex projectile motion scenarios, including air resistance
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Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for practical examples to illustrate these concepts.

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Homework Statement



hi, i was trying to figure out how to tackle this physics question, but I am a little stuck. the question is:

a tennis player, playing for a match hits a ball 2m above the groung. the ball leaves his racquet with a speed of 20m/s at an angle of 5 above the horizontal. the horizontal distance to the net is 7m and the net heigh is 1m does the ball clear the net?

i've diagram to help me and I am just stuck about where to start. thanks for helping me.

Homework Equations



i used v^2=u^2+2as and Vox=Vo*cos(angle) <- but i think I am wrong :S

The Attempt at a Solution


i got a=-28.57m/s. but and i got that it didn't claer the net. I am not sure wot i was doing really. :S
 
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sori i didn't mean too
 
You say you have found a value for "a" but "a" is not a speed it is acceleration. At least if you are using "a" as it is found in your equation.

v^2 = u^2 + 2as

Hint... the only acceleration in these sorts of problems is downward, ie. a = 9.81m/s^2. Friction from the air is generally ignored, unless it is specified as part of the problem.

Questions like these need to be solved in components. That is... what the ball does in its vertical motion and then.. horizontal motion. The two are quite indepenent.
 
Last edited:
ok thank you for help
 
Calculate the horizontal and vertical components of the velocity using trig.

In the x direction, where there is no acceleration, calculate how long it will take the ball to travel 7 m horizontally.

Then you can solve for how high the ball will be at this time, by using the equation

d = vit + 1/2at^2 in the y direction

Based upon the value of d, u can determine whether the ball cleared the net or not.
 

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