Does VBase / ZBase give IActual or IBase?

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tim9000
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If you took: VBase / ZBase

does that give you IActual

or IBase or what?

Because it seemed to give me IActual.

Cheers
 
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Simon Bridge said:
What is the difference?
Like if Iactual = Ibase*Iper unit
 
OK... so do that for the other "base" units.
Remember what the base and per unit parts mean.
What is the relationship between actual things?
 
Simon Bridge said:
OK... so do that for the other "base" units.
Remember what the base and per unit parts mean.
What is the relationship between actual things?
Well I know that Vbase / Zbase = (Vactual/Vpu) / (Zactual/Zpu)
=Vactual * Zpu / Vpu*Zactual = Iactual * (Zpu/Zactual)
But I'm not sure what that means for the last part of the last term
 
Sorry, the final term is wrong here:

Ibase=Vbase / Zbase = (Vactual/Vpu) / (Zactual/Zpu) =Vactual * Zpu / (Vpu*Zactual) = Iactual * (Zpu/Vpu)

Iactual * (Zpu/Vpu)=Iactual*Ipu
 
Babadag said:
Iactual * (Zpu/Vpu)=Iactual*Ipu

Oh right.
but Isn't (Zpu/Vpu) = 1 / Ipu

so Vbase / Zbase = Iactual / Ipu ?
Also, side question, say you were given the rated power and voltage for a system, so then you can work out the rated base impedance. But does that mean that
Ibase = √(Sbase - Zbase) ?
 
Sorry again. My mistake, this time : Vbase / Zbase = Iactual / Ipu, indeed.

Also for single phase system Ibase=sqrt(Sbase/Zbase) .So, what further?