(adsbygoogle = window.adsbygoogle || []).push({}); Does velocity "dammage" e=mc^2??

hi there, this is my first post in this forum, so i can begin to introduce myself:

i'm 17 years old and i really enjoy logic, as physics has matematics(that is logic) and make me think(use the brains, you know) i love it more than any other subject:tongue2: , i'm from Portugal.

So my question is about some concepts that i'm problaby getting confuse: already asked to several teachers about it but no1 could actually solve it defenetly...(and problaby is a stupid question), as I still haven't learnt in school relativity...

so we know that by general relativity that E=mc^2 (sorry, don't know how to post equations)

and we know too that "m" of a body is influenced by the relative speed of that body. m'=m/sqrt[1-(v^2)/(c^2)] or someting like that, at this time, i prefer to understand the concept, not the expression...

knowing that, i made an example to explain what's my point/question:

we have 2 persons "A" and "B", "A" is in a spaceship at 0.8c relative to referencial, "B" is "stoped" in relativity to the referencial. In the spaceship, there is a determinated quantity of Hidrogen. Imagine we can transform that all hidrogen in energy(total consuming of hidrogen trought E=mc^2)

At a determinated time, we decide to "transform" all that hidrogen in energy, creating a huge explosion.

My question is: what man, "A" or "B", receive more energy from the explosion?

considerating that the mass of the hidrogen is bigger in "B" than in "A" by the second premiss annouced above...

because this is really annoying me(in the good sense of course) is it actually possible more energy be recieved to another person only because he is moving in relation to something?? in that case, in a nuclear explosion, is better to stay stopped than trying to run away..:rofl:

thanks in advance, and hope don't take much time to you...

hope too to learn alot trought this forum...:P

regards, Littlepig

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# Does velocity dammage e=mc^2?

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