Domain and Derivative of 2[arctan(e^x)]?

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Homework Help Overview

The problem involves finding the domain and the first derivative of the function 2[arctan(e^x)], which falls under the subject area of calculus, specifically dealing with derivatives and function domains.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the domain of the arctan function and the exponential function, questioning the definitions and relationships between them. There is also a focus on the derivative of the composite function, with some participants expressing uncertainty about the correct form of the derivative.

Discussion Status

The discussion is active, with participants exploring the domain of the functions involved and clarifying misunderstandings about the derivative. Some guidance has been provided regarding the definitions of the functions, but no consensus has been reached on the derivative's form.

Contextual Notes

Participants are navigating confusion between domain and range, particularly regarding the exponential function, which has led to some misinterpretations in the discussion.

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Homework Statement


Find the domain and the first derivative of 2[arctan(e^x)]

Homework Equations


d/dx arctan(x)= 1/(1+x^2)

The Attempt at a Solution


I'm not sure about the domain...

For the derivative:
d/dx 2[arctan(e^x)] = 2 [1/(1+e^x)^2] (e^x)

But my teacher had the same answer excluding the e^x part. Isn't there supposed to be the e^x there since it is the derivative of the inside function?
 
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Yes, your teacher is wrong. But (1+e^x)^2 isn't the denominator. What should it be? To answer the domain question you first have to figure out the domain of arctan.
 
Oh right, the answer should be 2 [1/1+(e^x)^2]
The domain of arctan is (infinity, infinity)? (Since the function covers the entire graph)
 
Right, so put that together with the domain of e^x. Are there any values of x where the function isn't defined?
 
Well the graph of e^x looks like it's not defined anywhere below y=0. So would that mean the domain of e^x is x>0?
 
You are confusing the domain and the range of e^x. For what values of x (not y!) is e^x defined.
 
Oh, the domain is all reals then...so the domain of arctan(e^x) is all reals!
 
Yep. I agree.
 

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