- #1

- 1,914

- 46

## Homework Statement

L{sin(ωt)/[1+cos^2(ωt)]} =

## Homework Equations

d {arctan[cos(ωt)]} /dt =

- ω•sin(ωt)/[1+cos^2(ωt)]

## The Attempt at a Solution

∫e^(-st)•[sin(ωt)/(1+cos²(ωt)] dt =

-(1/ω)•∫e^(-st)•{arctan[cos(ωt)]}' dt =

= (integrating by parts and taking Re(s) > 0) =

= π/(4ω) -(s/ω)•∫ e^(-st)•arctan[cos(ωt)]

= π/(4ω) -(s/ω)•L{arctan[cos( ωt)]}.

But at this point I don't know how to compute the last laplace transform.

So I don't know if this is the best way or even if my question has a (simple) solution at all.

--

lightarrow

Last edited: