Domain and Range of the functions

Click For Summary
SUMMARY

The discussion focuses on determining the domain and range of two mathematical functions: f(x, y) = √((x - y) / (x + y)) and f(x, y) = ln(x² + y² + z²). For the first function, the domain requires x + y ≠ 0 and (x - y) / (x + y) ≥ 0, while the range is all positive real numbers. The second function's domain is constrained by the requirement that its argument, x² + y² + z², must be positive, thus ensuring the range is also real and positive.

PREREQUISITES
  • Understanding of functions with multiple variables
  • Knowledge of square root and logarithmic functions
  • Familiarity with domain and range concepts in mathematics
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of multi-variable functions
  • Learn about the implications of domain restrictions in calculus
  • Explore the behavior of logarithmic functions and their domains
  • Investigate inequalities involving rational expressions
USEFUL FOR

Students and educators in mathematics, particularly those focusing on calculus and algebra, as well as anyone needing clarity on the domain and range of complex functions.

kidia
Messages
65
Reaction score
0
Please can anybody help me on this two functions it confuse me because has two and thee variables.

Find the Domain and Range of each of the following functions

a)f(x,x)=[tex]\sqrt{\frac{x-y}{x+y}}[/tex]

b)f(x,y)=[tex]\[in{(x^2+y^2+z^2)}[/tex]
 
Physics news on Phys.org
a) x+y not equal to zero and (x-y/x+y)>=0, range should be all positive real

b) i assume that is Ln[x^2+y^2+z^2] then the argument can't be non-positive.

These functions map to one demensional space, so the range should be clear and obvious. Domain is similar to R^1, like positive argument under square root, divid by 0 etc.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K