Doppler effect and relative motion

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SUMMARY

The discussion centers on calculating the apparent frequency of a whistle emitting at 1200 Hz while moving south at 30.0 m/s, as perceived by an observer traveling north at 18.0 m/s. The correct formula to use is f = (v / (v - vs)) * fs, where v is the speed of sound (340 m/s), vs is the speed of the source, and vo is the speed of the observer. The correct apparent frequency calculated using the proper equation is 1044 Hz, confirming that the initial calculation of 1051 Hz was incorrect due to the misuse of the formula.

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  • Familiarity with relative motion concepts
  • Knowledge of wave frequency and speed equations
  • Ability to apply physics equations in real-world scenarios
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Hello everyone! I need some help with a Doppler effect/relative motion question.

Homework Statement


A whistle with a frequency of 1200 Hz is traveling south at a velocity of 30.0 m/s. You are traveling north away from the whistle at a speed if 18.0 m/s. If the speed of sound is 340 m/s, what is the apparent frequency of the whistle as heard by you? (Answer: 1044 Hz)

Homework Equations


f=(v/v+vs)fs

The Attempt at a Solution


Relative to myself, the train is moving at a speed of 48 m/s south and therefore away from me. Using the aforementioned equation I calculated frequency at 1051 Hz. Is the answer key wrong or am I missing something?
 
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The equation you have used is incorrect for the case when both source and observer are moving. Can you check in your notes or book for the correct one? It will have both speeds in it, vo and vs. You will also need to note that the velocity of the observer vo in the equation you should find will be negative if he's moving away from the source.
 

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