Doppler Effect change in the frequency Question

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SUMMARY

The discussion centers on calculating the change in frequency observed by a truck as a car with a horn frequency of 400Hz passes by it. The car travels at 40 m/s while the truck moves at 15 m/s, with the speed of sound set at 340 m/s. The correct formulas for the Doppler Effect in both scenarios—(a) when the vehicles are moving in the same direction and (b) when they are moving in opposite directions—are provided. The correct calculations involve determining the frequency when the car is both behind and ahead of the truck, leading to the conclusion that the initial solutions presented were incorrect.

PREREQUISITES
  • Doppler Effect principles
  • Understanding of sound wave frequency
  • Basic kinematics involving relative velocity
  • Mathematical manipulation of ratios and fractions
NEXT STEPS
  • Study the Doppler Effect equations for moving sources and observers
  • Practice problems involving sound frequency changes in various scenarios
  • Explore the impact of different speeds on frequency shifts
  • Learn about the applications of the Doppler Effect in real-world scenarios, such as radar and astronomy
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics and the Doppler Effect, as well as educators seeking to clarify concepts related to sound frequency changes in moving systems.

gr3g1
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Hey guys,
Im having lots of problems with this question..

A car moving at 40m/s and a truck moving at 15m/s travel along the same straight road. The car's horn has a natural frequency of 400Hz. What is the change in the frequency observed by the truck as the car passes the truck? Assume the car and the truck are traveling ( a) in the same direction and ( b) in opposite directions


Im using the car as the source, and the truck as the observer. The speed of sound is 340 m/s.

The solutions I got are:

a) [(340 + 15)/(340 - 40)] 400
b) [(340 - 15)/(340 + 40)] 400

according to the teachers answers, they are wrong..

Thanks in advance :)
 
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gr3g1 said:
Hey guys,
Im having lots of problems with this question..

A car moving at 40m/s and a truck moving at 15m/s travel along the same straight road. The car's horn has a natural frequency of 400Hz. What is the change in the frequency observed by the truck as the car passes the truck? Assume the car and the truck are traveling ( a) in the same direction and ( b) in opposite directions


Im using the car as the source, and the truck as the observer. The speed of sound is 340 m/s.

The solutions I got are:

a) [(340 + 15)/(340 - 40)] 400
b) [(340 - 15)/(340 + 40)] 400

according to the teachers answers, they are wrong..

Thanks in advance :)

The question seems to be to claculate the change of frequency as the car passes the truck.

when they are traveling in the same direction, calculate the frequency when the car is behind the truck, then calculate the frequency when the car is ahead of the truck. Subtract the two (the first will be larger, of course).

For b) calculate the frequency heard when the car ia in front of the truck (and coming toward it) and then when th ecar is behind (and moving away). Subtract the two.

If I understood the question correctly, thsi should give you the correct answers.

Pat
 

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