Doppler Effect Help: Solving Car Alarm Q with 21.06 m/s Speed

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SUMMARY

The discussion centers on a physics problem involving the Doppler Effect, specifically calculating the speed of a motorcycle moving away from a car alarm emitting sound waves at a frequency of 520 Hz. The user, Rhys, applied the Doppler Effect formula and calculated a listener's velocity of approximately 21.06 m/s to detect a frequency of 490 Hz. However, the answer was marked incorrect, prompting speculation about the car's potential movement affecting the frequency detected. The conversation highlights the importance of considering the source's motion in Doppler Effect calculations.

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ku1005
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Hey guys...or ladies...um...just wondering what I have done wrong for the following Q, it is an online Q i am doing and it tells me my answer is incorrect?


Q) "A car alarm is emitting sound waves of frequency 520 Hz. You are on a motorcycle, traveling directly away from the car."

"How fast must you be traveling if you detect a frequency of 490 Hz?
Enter your speed as a positive number. Take the speed of sound to be 344 m/s.


It seems fairly striaght forward, so I used the doppler effect (ie the wavelength must be greater and hence the frequency less if moving away)

so...

f(effetive) = v/(v+vl) . f

where vl = velocity of listener...

so i have

344/(344 . vl) . 520 = 490

solving for vl gives...21.06 ms^-1 roughly

so therfore, bke must be moving at 21.06ms^-1 ?

BUT it tells me this answer is incorrect??

any ideas appreciated!

cheers

rhys
 
Physics news on Phys.org
Nothing is wrong here. You may have to check if the car is stopdead or it may be moving at a certain speed.
 
mmm...program must b dodgi...cheers
 

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