Doppler Effect Stationary Source/Observer on a Spring

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SUMMARY

The discussion focuses on solving a physics problem involving the Doppler Effect with a stationary sound source and a microphone attached to a spring. The key parameters include a 540-Hz sound source, a microphone vibrating with a period of 2.20 seconds, and a frequency difference of 1.83 Hz. Participants emphasize the importance of using the equations for maximum and minimum observed frequencies to derive the maximum velocity and subsequently the amplitude of the microphone's motion. The equation v(max) = Aω is highlighted as essential for calculating amplitude once the maximum velocity is determined.

PREREQUISITES
  • Understanding of the Doppler Effect and its equations
  • Knowledge of simple harmonic motion and related formulas
  • Familiarity with calculus, specifically differentiation
  • Ability to manipulate and solve equations involving frequency and velocity
NEXT STEPS
  • Study the derivation of the Doppler Effect equations for stationary sources
  • Learn how to apply calculus to derive relationships in simple harmonic motion
  • Explore the relationship between amplitude and maximum velocity in oscillatory systems
  • Practice solving similar physics problems involving sound waves and harmonic motion
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics and harmonic motion, as well as educators looking for problem-solving strategies in acoustics.

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Homework Statement


A microphone is attached to a spring that is suspended from the ceiling. Directly below on the floor is a stationary 540-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 2.20 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 1.83 Hz. Ignoring any reflections of sound in the room and using 343 m/s for the speed of sound, determine the amplitude (in m) of the simple harmonic motion.

Homework Equations


f(obs)= f(source) (1-(v(obs)/v))
ω=2\pi/T
v(max)=Aω

The Attempt at a Solution


When I inquired about help I was told that I need to combine the equations for the max and min frequencies to get the maximum velocity, but I can't figure out how to do that. I am also not sure what to do with the difference of the max and min frequencies that was given in the problem. I have figured the value of ω to be 2.86 rad/s.

I think I would use the equation v(max)=Aω once I had the max velocity to get the amplitude.

I feel like this problem should be easier but I just can't figure it out!
 
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combine the equations for the max and min frequencies
Write your dopplar equation twice, once with positive Vo and again with negative Vo. One gives the maximum frequency observed, the other the minimum, so the difference between the two is your 1.83 Hz. That's your clue to subtract the two equations. I think you will be able to get Vo out of that.

Regarding the amplitude, I wonder if you have an equation something like
x = A*sin(ωt) for the position as a function of time. And can differentiate it with respect to time to get a similar equation for the velocity. The two of them would constitute a relationship between the amplitude and the maximum velocity.
 
Thank you so much! I just subtracted the min frequency from the max and set it equal to 1.83 Hz.

I did, however, use the v(max)=Aω to find the amplitude, but versus time the other equation would have worked better.

:)
 
Most welcome!
v(max)=Aω comes from differentiating x = A*sin(ωt).
 
Didn't even notice that, I haven't thought about differentiation (or calculus) in a few semesters :)
 

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