Doppler Effect + Wavelength problem

AI Thread Summary
The discussion centers on a problem involving the Doppler Effect and calculating the wavelength of sound as perceived by a moving listener. The sound source emits a frequency of 210 Hz, while the listener moves towards it at 85 m/s. The adjusted frequency (f') calculated using the Doppler formula is 262.5 Hz. The wavelength is determined using the speed of sound in still air (340 m/s) and the new frequency, resulting in a wavelength of approximately 1.295 meters. The key takeaway is that the wavelength is derived from the speed of sound divided by the adjusted frequency, reflecting the listener's motion towards the source.
KendrickLamar
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Homework Statement



A sound source emits sounds of frequency 210 Hz that travel through still air at 340 m/s. The listener moves at 85 m/s relative to still air toward the stationary source. What is the wavelength of the sound between the source and the listener?

Homework Equations



f' = f[1+ Vlistener/Vsound]
v=(wavelength)f

The Attempt at a Solution


well using the doppler effect since the listener is moving towards the stationary source i know it will be f'=f[1+Vlistener/Vsound]

i find the f' right... but when using v=wavelength*frequency, which frequency do i actually use. because i know although I am solving for f' , I am just wondering if its a trick or something because I'm a little confused on the concept.

so for f' i get 262.5 Hz

then i plug it into the v=wavelength*freq , but which velocity do i use? the speed of sound or the speed of the listener moving?

using the speed of sound i get 340 m/s = wavelength * 262.5 and end up with 1.295m as the wavelength.
 
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If the source is not moving the waves are unchanged and their wavelength is simply given by v/f where v is their speed in still air and f the original frequency.
The frequency of the sound heard by the moving listener is higher because he passes through the approaching waves at a higher rate than if he were stationary. The Doppler formula will give this new frequency.
 
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