Doppler Effect Homework: Find Speed of Ambulance

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SUMMARY

The discussion revolves around calculating the speed of an ambulance using the Doppler Effect, with an observed frequency of 480 Hz as it approaches and 420 Hz as it recedes. The speed of sound in air is given as 343 m/s. The correct formulae used are f' = (vf)/(v - vs) for approaching and f' = (vf)/(v + vs) for receding sources. The user initially attempted to estimate the source frequency incorrectly but ultimately resolved the problem with algebraic manipulation.

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  • Familiarity with frequency and wave equations
  • Basic algebra skills
  • Knowledge of sound speed in air (343 m/s)
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Homework Statement


A stationary observer at a crosswalk hears an ambulance siren with an apparent frequency of
480 Hz when the ambulance is approaching. After the ambulance passes the apparent frequency is only 420 Hz. Find the speed of the ambulance. Assume v = 343 m/s for the speed of sound in air.

Homework Equations


source moving towards observer: f' = (vf)/(v - vs)
source moving away from observer: f' = (vf)/(v + vs)

The Attempt at a Solution


I am having trouble because I am not sure how to figure out what the frequency of the sound given off by the ambulance is. I tried using 450 since it is halfway between, and it gave me a close answer, but not the correct one. Any help would be much appreciated.

Thanks a lot
 
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hi asdf12321asdf! :smile:
asdf12321asdf said:
source moving towards observer: f' = (vf)/(v - vs)
source moving away from observer: f' = (vf)/(v + vs)

The Attempt at a Solution


I am having trouble because I am not sure how to figure out what the frequency of the sound given off by the ambulance is. I tried using 450 since it is halfway between, and it gave me a close answer, but not the correct one.

Quelle surprise! :smile:

c'mon … use some algebra! :wink:
 
oh ok I figured it out thanks a lot
 

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